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Gre4nikov [31]
2 years ago
8

Suppose that the duration of a particular type of criminal trial is known to be normally distributed with a mean of 21 days and

a standard deviation of seven days. a. In words, define the random variable X. a. The duration of a criminal trial b. X ~ _N____(___21__,__7___) c. If one of the trials is randomly chosen, find the probability that it lasted at least 24 days. Sketch the graph and write the probability statement.
Mathematics
1 answer:
Black_prince [1.1K]2 years ago
6 0

Answer:

0.33411

The probability that a particular criminal trial lasted atleast 24 days is 0.33411

Step-by-step explanation:

The random variable X is normally distributed with a mean of 21 and standard deviation of 7

;

X ~ N(μ = 21 ; σ = 7)

X ~ N(21, 7)

Probability that a trial lasted atleast 24 days :

P(X ≥ 24) :

The standardized score :

Z = (x - μ) / σ ; (24 - 21) / 7 ; 3 / 7 = 0.4286

Hence,

P(Z ≥ 0.4286) = 0.33411

The probability that a particular criminal trial lasted atleast 24 days is 0.33411

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For this case, the first thing we are going to do is write the generic equation of motion for the vertical axis.

We have then:

h = \frac {1} {2} gt ^ 2 + vo * t + h0

Where,

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For the first body:

h1 = \frac {1} {2} gt ^ 2 + \frac {8} {12} * t + 21

For the second body:

h2 = \frac {1} {2} gt ^ 2 - \frac {11} {12} * t + 50

By the time both bodies have the same height we have:

h1 = h2\\

\frac {1} {2} gt ^ 2 + \frac {8} {12} * t + 21 = \frac {1} {2} gt ^ 2 - \frac {11} {12} * t + 50

Rewriting we have:

\frac {8} {12} * t + 21 = - \frac {11} {12} * t + 50

\frac {8} {12} * t + \frac {11} {12} * t = 50 - 21

\frac {19} {12} * t = 29

Clearing time:

t = 29 (\frac {12} {19})\\t = 18.31s

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Answer:

<h3>10</h3>

Step-by-step explanation:

If point I is on the line segment HJ, then HI+IJ = HJ

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