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bulgar [2K]
2 years ago
14

Tom went on a bike to the store 3 miles away. If it took Tom 1/2 of an hour to get there and 2/3 of an hour to get back , what w

as his average rate of speed for the entire trip
Mathematics
1 answer:
anastassius [24]2 years ago
8 0

Answer:

5.14 mi/h

Step-by-step explanation:

To find the average speed, we simply find the total distance traveled by Tom and divide that by the total time the entire journey took him.

Average speed = (total distance traveled) / (total time taken)

TOTAL DISTANCE TRAVELED

He traveled 3 miles to and 3 miles fro. Hence:

3 + 3 = 6 miles

TOTAL TIME TAKEN

He spent ½ hr to go and ⅔ hr to return back. Hence:

½ + ⅔ = 7/6 hr

Therefore, the average speed is:

v = 6 / (7/6)

v = 36 / 7 = 5.14 mi/h

Tom's average speed was 5.14 mi/h.

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A seamstress has a piece of cloth that is 3 yards long. She cuts it into shorter lengths of 16 inches each. How many of the shor
harkovskaia [24]
She can cut 6 pieces. Here's how.
Three yards are 108 inches, 16 can go into 108, 6.75 times.
4 0
2 years ago
John is filling a bathtub that is 18 inches deep. He notices it takes 2 mins. To fill the tub 3 inches of water. He estimates it
Pavel [41]

Depth of the bathtub = 18 inches

Time taken to fill 3 inches of the bathtub = 2 minutes

Then

The amount of depth needed to fill with water = (18-3) inches

                                                                        = 15 inches

Time required to fill 15 inches of the bathtub = (15*2)/3 minutes

                                                                      = 30/3 minutes

                                                                      = 10 minutes

So John is correct in thinking that it will take 10 more minutes for the water to reach the top of the tub if he continues at the same rate.

Hope this helps!

6 0
2 years ago
Read 2 more answers
b. Sixty-five pounds of candy was divided into four different boxes. The second box contained twice the amount of the first box.
Ainat [17]

First box = 14 pounds

Second box = 2x = 28 pounds

Third Box = x+2= 16 pounds

Fourth box = x/2 = 7 pounds

<u>Step-by-step explanation:</u>

Here we have , Sixty-five pounds of candy was divided into four different boxes. The second box contained twice the amount of the first box. The third box contained two more pounds than the first box. The last box contained one-fourth the amount in the second box. We need to find How much candy was in each box. Let's find out:

We have a total of 65 pounds of candy ! Let in first box we have x pounds so , second box contained twice the amount of the first box i.e.

⇒ 2x

The third box contained two more pounds than the first box i.e.

⇒ x+2

The last box contained one-fourth the amount in the second box i.e.

⇒ (\frac{1}{4})2x = \frac{x}{4}

Therefore , Sum of pounds of candy are :

⇒ \frac{x}{2} +x+2+2x+x=65

⇒ \frac{x}{2} +4x=63

⇒ \frac{9x}{2}=63

⇒ x=63(\frac{2}{9} )

⇒ x=14

Therefore , Candy in each box is :

First box = 14 pounds

Second box = 2x = 28 pounds

Third Box = x+2= 16 pounds

Fourth box = x/2 = 7 pounds

8 0
2 years ago
How to factor quadratics like <br> 2<br> 3x^+31x+36
anzhelika [568]

Answer:

3(x32+12)

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Find the missing probability. P(A)=15,P(A∪B)=1225,P(A∩B)=7100 ,P(B)=?
Llana [10]

Answer:

<h2>p(B) = 8310</h2>

Step-by-step explanation:

We will use the addition rule of probability of two events to solve the question. According to the rule given two events A and B;

p(A∪B) = p(A)+p(B) - p(A∩B) where;

A∪B is the union of the two sets A and B

A∩B is the intersection between two sets A and B

Given parameters

P(A)=15

P(A∪B)=1225

P(A∩B)=7100

Required

Probability of event B i.e P(B)

Using the expression above to calculate p(B), we will have;

p(A∪B) = p(A)+p(B) - p(A∩B)

1225 = 15+p(B)-7100

p(B) = 1225-15+7100

p(B) = 8310

Hence the missing probability p(B) is 8310.

6 0
2 years ago
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