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2 years ago

Andrew invested $20,000 in mutual funds and received a sum of $35,000 at the end of the investment period. Calculate the ROI.

1 answer:

5 0

Answer: $15,000

As $35,000-$20,000=$15,000.

That's basically the profit he had made, or the return on his investment (ROI).

As he already had $20,000, he had "only" made $15,000.

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Which multiplication equation can be used to explain the solution to 15 divided by 1/3

Anastaziya [24]

Answer:Multiply by the reciprocal, also sometimes referred to as "Keep, Change, Flip." Here is how it works. You rewrite the division question as a multiplication question by flipping the second fraction over. Next, keep the first number, change the division to multiplication and then flip the second fraction over.

Step-by-step explanation:

4 0

2 years ago

The bookstore marked some notepads down from ???$ 3.00 but still kept the price over ???$ 2.00. It sold all of them. The total a

Anna71 [15]

The answer is 13. To figure this out I used 10 notebooks sold as a guide. I knew the answer could not be 10, because $27.95/10 was not a number stopping in the hundredths place (or a true money amount).

I tried numbers greater than 10 using a trial and error strategy until I got to 13 notebooks sold and found that it $27.95 was divisible by 13 to get an answer between $2 and $3 ($2.15 exactly).

3 0

2 years ago

To increase an amount by 7% what single multiplier would you use?

vazorg [7]

You would multiply by 1.7

8 0

2 years ago

Read 2 more answers

Solve the given initial value problem and determine how the interval in which the solution exists depends on the initial value y

zalisa [80]

Answer:

y has a finite solution for any value y_0 ≠ 0.

Step-by-step explanation:

Given the differential equation

y' + y³ = 0

We can rewrite this as

dy/dx + y³ = 0

Multiplying through by dx

dy + y³dx = 0

Divide through by y³, we have

dy/y³ + dx = 0

dy/y³ = -dx

Integrating both sides

-1/(2y²) = - x + c

Multiplying through by -1, we have

1/(2y²) = x + C (Where C = -c)

Applying the initial condition y(0) = y_0, put x = 0, and y = y_0

1/(2y_0²) = 0 + C

C = 1/(2y_0²)

1/(2y²) = x + 1/(2y_0²)

2y² = 1/[x + 1/(2y_0²)]

y² = 1/[2x + 1/(y_0²)]

y = 1/[2x + 1/(y_0²)]½

This is the required solution to the initial value problem.

The interval of the solution depends on the value of y_0. There are infinitely many solutions for y_0 assumes a real number.

For y_0 = 0, the solution has an expression 1/0, which makes the solution infinite.

With this, y has a finite solution for any value y_0 ≠ 0.

8 0

2 years ago

If the pointer in the figure is spun twice, find the probability that the pointer lands on red (R) both spins.

r-ruslan [8.4K]

The probability of the pointer lands on red(R) both spin = $\frac{1}{36}$

Step-by-step explanation:

Given,

The number of parts = 6

The pointer is spun twice.

To find the probability of the pointer lands on red(R) both spin.

Formula

Probability of an event = number of required outcomes ÷ the total number of outcomes.

P(A and B) = P(A)×P(B)

Now,

For one spin,

A = RED comes.

For second spin,

B = RED comes

So,

P(A) = $\frac{1}{6}$ and P(B) = $\frac{1}{6}$

Then,

P(A and B) = $\frac{1}{6}$ × $\frac{1}{6}$ = $\frac{1}{36}$

Hence, the probability of the pointer lands on red(R) both spin = $\frac{1}{36}$

4 0

2 years ago