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GrogVix [38]
1 year ago
8

How many intersections are there of the graphs of the equations below? One-halfx + 5y = 6 3x + 30y = 36 none one two infinitely

many
Mathematics
2 answers:
Keith_Richards [23]1 year ago
5 0

Answer:

infinitely many

Step-by-step explanation:

  • 1/2x + 5y = 6 ⇒ x+10y=12
  • 3x + 30y = 36 ⇒ x+10y=12

As we see, these are equal lines, they overlap, so there are infinitely many intersections

Sergeu [11.5K]1 year ago
4 0

Answer:

infinitely many

Step-by-step explanation:

You have the system

(1/2)x + 5y = 6

  3x  + 30y = 36

Multiplying the first equation by 6 results in 3x + 30y = 36, which is exactly the same as the second equation.  The two graphs coincide, and so there are infinitely many solutions to this system

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Answer:

Step-by-step explanation:

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the midpoint of segment MN is Point G (10,8). One endpoint is M (6,9). What are the coordinates of Point N, the other midpoint?
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Explain how a function graph can be used to help verify that a function is factored correctly
Sergeeva-Olga [200]

By factorising a function, you can find the value of x-intercepts by substituting f(x)=0

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Which expression is equivalent to x Superscript negative five-thirds? StartFraction 1 Over RootIndex 5 StartRoot x cubed EndRoot
Anastasy [175]

Option B : \frac{1}{\sqrt[3]{x^{5} } } is the expression equivalent to x^{-\frac{5}{3}

Explanation:

The given expression is x^{-\frac{5}{3}

Rewriting the expression x^{-\frac{5}{3} using the exponent rule, $a^{-b}=\frac{1}{a^{b}}$

Hence, we get,

\frac{1}{x^{\frac{5}{3} } }

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Applying the rule, a^{\frac{1}{n}}=\sqrt[n]{a}

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\frac{1}{\sqrt[3]{x^{5} } }

Now, we shall determine from the options that which expression is equivalent to x^{-\frac{5}{3}

Option A: \frac{1}{\sqrt[5]{x^{3} } }

The expression \frac{1}{\sqrt[5]{x^{3} } } is not equivalent to simplified expression  \frac{1}{\sqrt[3]{x^{5} } }

Thus, the expression \frac{1}{\sqrt[5]{x^{3} } } is not equivalent to x^{-\frac{5}{3}

Hence, Option A is not the correct answer.

Option B: \frac{1}{\sqrt[3]{x^{5} } }

The expression \frac{1}{\sqrt[3]{x^{5} } } is equivalent to the simplified expression  \frac{1}{\sqrt[3]{x^{5} } }

Thus, the expression \frac{1}{\sqrt[3]{x^{5} } } is equivalent to x^{-\frac{5}{3}

Hence, Option B is the correct answer.

Option C: -\sqrt[3]{x^5}

The expression -\sqrt[3]{x^5} is not equivalent to the simplified expression \frac{1}{\sqrt[3]{x^{5} } }

Thus, the expression -\sqrt[3]{x^5} is not equivalent to x^{-\frac{5}{3}

Hence, Option C is not the correct answer.

Option D: -\sqrt[5]{x^3}

The expression -\sqrt[5]{x^3} is not equivalent to the simplified expression \frac{1}{\sqrt[3]{x^{5} } }

Thus, the expression -\sqrt[5]{x^3} is not equivalent to x^{-\frac{5}{3}

Hence, Option D is not the correct answer.

4 0
1 year ago
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Answer:

The function that would correctly calculate the 90% range of likely sample means is given by:

B. 4,200±CONFIDENCE.T(0.10,140,12)

Step-by-step explanation:

In Microsoft Excel, the syntax

CONFIDENCE.T(alpha,standard-dev,size)  returns the confidence  interval for the population mean, using the students T-distribution.Alpha=1-90\%=10\%=0.10

The standard deviation is given as $140 and the sample size is 12.

In constructing the confidence  interval we use:

\bar X\pm CONFIDENCE.T(alpha,standard-dev,size)  

Let us substitute the values to get:

4,200\pm CONFIDENCE.T(0.10,140,12)

We use the T distribution because \sigma is unknown

8 0
1 year ago
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