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mafiozo [28]
2 years ago
15

A recipe for lemon cranberry pound cake calls for 80 milliliters of lemon juice and 240 milliliters of plain yogurt. How many li

ters of lemon juice and yogurt are needed to make 11 cakes?
Mathematics
2 answers:
igor_vitrenko [27]2 years ago
7 0
We know that
1 liter------------> is equal to 1000 ml

if for one cake--------------> are required 80 milliliters of lemon juice
<span> for 11 cakes--------------> X
X=11*80---------> 880 ml

</span>if for one cake--------------> are required 240 milliliters of plain yogurt
 for 11 cakes--------------> X
X=11*240---------> 2640 ml

<span>liters of lemon juice needed to make 11 cakes
880 ml/1000------> 0.88 lt

</span><span>liters of yogurt needed to make 11 cakes
2640 ml/1000--------> 2.64 lt

the answer is
are needed 0.88 lt </span>of lemon juice and 2.64 lt of yogurt to make 11 cakes<span>

</span>
storchak [24]2 years ago
7 0

Answer: 3 liters 520 milliliters

Step-by-step explanation:

Total liquid amount:

80 ml + 240 ml = 320 milliliters

Total amount for 11 cakes:

320 milliliters × 11 = 3,520 milliliters

Total amount for 11 cakes conversion:

3,520 milliliters ÷ 1,000 = 3 remainder 520 = 3 liters 520 milliliters

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Sloan [31]

Answer:

a) 6

Step-by-step explanation:

Expanding the polynomial using the formula:

$(x+y)^n=\sum_{k=0}^n \binom{n}{k} x^{n-k} y^k $

Also

$\binom{n}{k}=\frac{n!}{(n-k)!k!}$

I think you mean 210x^6y^4

We can deduce that this term will be located somewhere in the middle. So I will calculate k= 5; k=6 \text{ and } k =7.

For k=5

$\binom{10}{5} (y)^{10-5} (x)^{5}=\frac{10!}{(10-5)! 5!}(y)^{5} (x)^{5}= \frac{10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5! }{5! \cdot 5 \cdot 4 \cdot 3 \cdot 2 \cdot 1 } \\ =\frac{30240}{120} =252 x^{5} y^{5}$

Note that we actually don't need to do all this process. There's no necessity to calculate the binomial, just x^{n-k} y^k

For k=6

$\binom{10}{6} \left(y\right)^{10-6} \left(x\right)^{6}=\frac{10!}{(10-6)! 6!}\left(y\right)^{4} \left(x\right)^{6}=210 x^{6} y^{4}$

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2 years ago
A steel pipe 100 cm long has an outside diameter of 2 cm and an inside diameter of 1.8 cm. If thee density of the steel is 7.8 g
ELEN [110]

Answer:

The mass of the pipe is 465\ g

Step-by-step explanation:

step 1

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The volume is equal to the area of outside circle minus the area of inside circle, multiplied by the length of the pipe

so

V=\pi [r2^{2}-r1^{2}]L

we have

r2=2/2=1\ cm ---> the radius is half the diameter

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V=(3.14)[1^{2}-0.9^{2}](100)=59.66\ cm^{3}

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The mean hourly wage for employees in goods-producing industries is currently $24.57 (Bureau of Labor Statistics website, April,
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Answer:

a. H_{0}: μ = $24.57

H_{a}: μ ≠ $24.57

b. 0.12

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z-score can be calculated as follows:

\frac{X-M}{\frac{s}{\sqrt{N} } } where

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Putting the numbers in the formula we get

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The corresponding p-value is <em>two tailed </em>and  ≈ 0.12

c)

since p ≈0.12 > 0.05 <em>we fail to reject the null hypothesis.</em>

d)

Critical value for the 0.05 significance level in two tailed test is :

c(z)=-1.96 Since z≈ −1,6 >-1.96, it is not in the critcal region, therefore <em>we fail to reject the null hypothesis. </em>

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