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1 year ago

The diagram shows a circle inside a square. a O 16 cm Work out the area of the circle.

Mathematics

1 answer:

LuckyWell [14K]1 year ago

4 0

Answer:

perimeter of circle=2πr

16=2πr

r=16/2π=8/πcm

now.

area of circle=πr²=π(8/π)²=π×64/π²=64/(22/7)=64×7/22=20.36cm²

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The area of a right triangle is 210 square inches. The height of the right triangle is 35 inches.

deff fn [24]

35 squared + 35 squared
rad 2450
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2 years ago

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What type of triangle has side lengths 12, 13, and 2√3?

Travka [436]

Answer:

The triangle is an obtuse scalene triangle

Step-by-step explanation:

we know that

if $c^{2}=a^{2}+b^{2}$ --------> is a right triangle

if $c^{2}>a^{2}+b^{2}$ --------> is an obtuse triangle

if $c^{2}$ --------> is an acute triangle

where

c is the greater side

we have

$c=13\ units$

$a=12\ units$

$b=2\sqrt{3}\ units$

$c^{2}=13^{2}=169$

$a^{2}+b^{2}=12^{2}+(2\sqrt{3})^{2}=156$

$c^{2}>a^{2}+b^{2}$ -------> is an obtuse triangle

Remember that

The given triangle has three different length side

Is a scalene triangle

therefore

The triangle is an obtuse scalene triangle

4 0

2 years ago

The Stolen Book. Betty tells Susan that Bob stole her business law book from her car. The next day Susan confronts Bob and slaps

leva [86]

I believe it is a hope this helps

3 0

2 years ago

15 Points!

goblinko [34]

Answer:

coordinate of point A is (a,b)

coordinate of point C is (2c,d)

slope of AD and BC = $\frac{b}{a-c}$

Step-by-step explanation:

According to midpoint formula

If we have points P $(x_{1} ,y_{1} )$ and Q $(x_{2} ,y_{2} )$

then the coordinate (x,y) of mid point of line PQ is given by

$x=\frac{x_{1} +x_{2} }{2}$ and $y=\frac{y_{1} +y_{2} }{2}$

now from the given diagram A is the mid point of line joining R(0,0) and S(2a,2b)

Using midpoint formula, coordinates of point A is given by

$x=\frac{0+2a}{2}= a$ and $y=\frac{0+2b}{2} =b$

so we have

coordinate of point A is (a,b)

Also C is the midpoint of line joining T (2c,2d) and V(2c,0)

coordinate of point C is given by

$x= \frac{2c+2c}{2} =2c$ and $y=\frac{2d+0}{2} =d$

so we have

coordinate of point C is (2c,d)

it is given that coordinate of point B is (a+c, b+d) and coordinate of D is (c,0)

If we have points P $(x_{1} ,y_{1} )$ and Q $(x_{2} ,y_{2} )$

then the slope of PQ = $\frac{y_{2} -y_{1} }{x_{2}-x_{1} }$

hence slope of AD= $\frac{0-b }{c-a}$

= $\frac{-b}{c-a}$

= $\frac{-b}{-(a-c)}$

= $\frac{b}{a-c}$

and slope of BC = $\frac{d-(b+d)}{2c-(a+c)}$

= $\frac{d-b-d}{2c-a-c}$

= $\frac{-b}{c-a}$

= $\frac{b}{a-c}$

so we have

slope of AD and BC = $\frac{b}{a-c}$

7 0

2 years ago

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What is the PV of an ordinary annuity with 10 payments of $2,700 if the appropriate interest rate is 5.5%? Group of answer choic

Verizon [17]

Answer:

The PV of an ordinary annuity with 10 payments of $2,700 if the appropriate interest rate is 5.5% is $20,352.

Step-by-step explanation:

P = PMT [(1 - (1 / (1 + r) $^{n}$ )) / r]

= 2,700 [(1 - (1 / (1 + 0.055) $^{10}$ )) / 0.05]

= 2,700 [(1 - (1 / (1.708)) / 0.05]

= 2,700 [(1 - 0.58)) / 0.05]

= 2,700 [(0.41457) / 0.05]

= 2,700(7.53)

=$ 20,352

5 0

2 years ago