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2 years ago

Sue played four games of golf.

Mathematics

2 answers:

alisha [4.7K]2 years ago

7 0

Answer:

Sue's scores for the four games in ascending order are: 97, 98, 98, 107

Step-by-step explanation:

Her modal score was 98. The mode is found by using the number that appears most often. This means that 98 has to appear at least two times out of the four scores.

Her range was 10. The range is found by taking the highest score and subtracting it from the lowest score. The highest score had to be greater than 98 and the lowest score had to be less than 98 since we know the mode was 98.

Her mean score was 100. This mean is found by adding all the numbers together and then dividing by the total numbers listed. Adding the four scores together and dividing by 4 will equal 100.

Used guess and test:

Highest Number, 98, 98, Lowest Number

107 - 97 = 10 (meets range requirement)

97 + 98 + 98 + 107 = 400

400/4 = 100 (meets the mean requirement)

lina2011 [118]2 years ago

6 0

Answer:

idk

Step-by-step explanation:

You might be interested in

If cos(t) = 2/7 and t is in the 4th quadrant, find sin(t).

Yuliya22 [10]

We can use the Pythagorean Trigonometric Identity which says:
$sin^2(t)+cos^2(t)=1$

Since we need to find sin(t), we have to solve for it:
$sin(t)= \sqrt{1-cos^2(t)}$

Let's plug in the given cos(t) value:
$sin(t) = \sqrt{1-cos^2( \frac{2}{7})}$

And solve sin(t):
$sin(t) = \sqrt{1- \frac{4}{49} } = \frac{x}{y} \sqrt{ \frac{49}{49}- \frac{4}{49} }$

Simplify further:
$sin(t) = \sqrt{ \frac{45}{49} } = \frac{ \sqrt{45} }{7} = \frac{ \sqrt{9*5} }{7}$

And it all simplifies down to:
$sin(t) = \frac{3 \sqrt{5} }{7}$

Since it's in the 4th quadrant, the sin(t) value is going to be negative. So, your final answer is:
$sin(t) = - \frac{ 3\sqrt{5} }{7}$

Hope this helps!

7 0

2 years ago

The diagram shows a square (6x -1)cm (4x+6)cm find the length of the side of the square

sammy [17]

Answer:

3.5 cm

Step-by-step explanation:

6x-1=4x+6

6x-4x=1+6

2x=7

x=7÷2

x=3.5

I hope my answer will help you and i guess it's correct

7 0

2 years ago

A population consists of the following five values: 1, 3, 4, 4, and 6. List all samples of size 2 from left to right without rep

aniked [119]

Answer:

The sample of sizes 2 and their mean are given below.

Step-by-step explanation:

The population consist of 5 values, S = {1, 3, 4, 4, 6}.

The number of samples of size 2 (without replacement) that can be formed from these 5 values is:

${5\choose 2}=\frac{5!}{2!(5-2)!} =10$

Th formula to compute the mean is:

$\bar x=\frac{1}{n}\sum x_{i}$

List the 10 samples and their mean as follows:

<u>Sample</u> <u>Mean</u>

(1, 3) $\bar x=\frac{1}{2}[1+3]=\frac{4}{2}=2.0$

(1, 4) $\bar x=\frac{1}{2}[1+4]=\frac{5}{2}=2.5$

(1, 6) $\bar x=\frac{1}{2}[1+6]=\frac{7}{2}=3.5$

(3, 4) $\bar x=\frac{1}{2}[3+4]=\frac{7}{2}=3.5$

(3, 6) $\bar x=\frac{1}{2}[3+6]=\frac{9}{2}=4.5$

(4, 4) $\bar x=\frac{1}{2}[4+4]=\frac{8}{2}=4.0$

(4, 6) $\bar x=\frac{1}{2}[4+6]=\frac{10}{2}=5.0$

8 0

2 years ago

Let f(x)=4x-1 and g(x)=2x^2+3. Perform each function operations and then find the domain.

Triss [41]

F(x) = 4x - 1
g(x) = 2x² + 3

1. (f + g)(x) = (4x - 1) + (2x² + 3)
(f + g)(x) = 2x² + 4x + (-1 + 3)
(f + g)(x) = 2x² + 4x + 2
Domain: {x| -∞ < x < ∞}, (-∞, ∞)

2. (f - g)(x) = (4x + 1) - (2x² + 3)
  (f - g)(x) = 4x + 1 - 2x² - 3
(f - g)(x) = -2x² + 4x + 1 - 3
(f - g)(x) = -2x² + 4x - 2
Domain: {x|-∞ < x < ∞}, (-∞, ∞)
3. (g - f)(x) = (2x² + 3) - (4x - 1)
(g - f)(x) = 2x² + 3 - 4x + 1
(g - f)(x) = 2x² - 4x + 3 + 1
(g - f)(x) = 2x² - 4x + 4
Domain: {x| -∞ < x < ∞}, (-∞, ∞)

4. (f · g)(x) = (4x + 1)(2x² + 3)
(f · g)(x) = 4x(2x² + 3) + 1(2x² + 3)
(f · g)(x) = 4x(2x²) + 4x(3) + 1(2x²) + 1(3)
(f · g)(x) = 8x³ + 12x + 2x² + 3
(f · g)(x) = 8x³ + 2x² + 12x + 3
Domain: {x| -∞ < x < ∞}, (-∞, ∞)

5. $(\frac{f}{g})(x) = \frac{4x - 1}{2x^{2} + 3}$
Domain: 2x² + 3 ≠ 0
- 3 - 3
2x² ≠ 0
2 2
  x² ≠ 0
x ≠ 0
(-∞, 0) ∨ (0, ∞)

6. $(\frac{g}{f})(x) = \frac{2x^{2} + 3}{4x - 1}$
Domain: 4x - 1 ≠ 0
+ 1 + 1
4x ≠ 0
4   4
x ≠ 0
  (-∞, 0) ∨ (0, ∞)

6 0

2 years ago

the required condition for using an anova procedure on data from several populations for mean comparison is that the

Anuta_ua [19.1K]

Answer:

The sampled populations have equal variances

Step-by-step explanation:

ANOVA which is fully known as Analysis of variances can be defined as the collection of statistical models as well as their associated estimation procedures which enables easily and effectively analyzis of the differences among various group means in a sample reason been that ANOVA is a total variance in which the observed variance in a specific variable is been separated into components which are attributable to various sources of variation which is why ANOVA help to provides a statistical test to check whether two or more population means are equal.

Therefore the required condition for using an ANOVA procedure on data from several populations for mean comparison is that THE SAMPLED POPULATION HAVE EQUAL VARIANCE.

5 0

2 years ago