Answer:
The 95 percent confidence interval for the mean of the population from which the study subjects may be presumed to have been drawn is (19.1269, 32.6730).
Step-by-step explanation:
Intern No. of Breast
Number Exams Performed X²
1 30 900
2 40 1600
3 8 64
4 20 400
5 26 676
6 35 1225
7 35 1225
8 20 400
9 25 625
<u>10 20 400 </u>
<u> </u><u> ∑ 259 ∑ 7515</u>
Mean= X`= ∑x/n= 259/10= 25.9
Variance = s²= 1/n-1[∑X²- (∑x)²/n]
= 1/0[7515- (259)²/10]= 1/9[7515- 6708.1]
= 806.9/9=89.655= 89.66
Standard Deviation= √89.655= 9.4687
Hence
The value of t with significance level alpha= 0.05 and 9 degrees of freedom is t(0.025,9)= 2.262
The 95 % Confidence interval is given by
x`±t(∝,n-1) s/√n
So Putting the values
25.9± 2.262( 9.4687/√10)
= 25.9 ±2.262 (2.9943)
= 25.9 ± 6.7730
= 25.9 +6.7730=32.6730
25.9 -6.7730= 19.1269
= 19.1269, 32.6730
The 95 percent confidence interval for the mean of the population from which the study subjects may be presumed to have been drawn is (19.1269, 32.6730).
Answer:
The price for each kilogram of strawberries is $7.50
Step-by-step explanation:
<u><em>The question is</em></u>
Blues berry farm charges Percy a total of $24.75 for entrance and 2.5 kilograms of strawberries. The entrance fee is $6 and the price for each kilogram of strawberries is constant
Determine the price for each kilogram of strawberries
Let
x ----> the price for each kilogram of strawberries
we know that
The entrance fee plus the price of each kilogram of strawberries multiplied by the number of kilogram of strawberries must be equal to $24.75
so
The linear equation that represent this situation is

solve for x
subtract 6 both sides

divide by 2.5 both sides

therefore
The price for each kilogram of strawberries is $7.50
Step-by-step explanation:
The line of best fit is y = 2.599x + 105.08. At x = 20, the estimated height is y = 157.06. The actual height is 160 cm, so the residual is:
160 cm − 157.06 cm = 2.94 cm
<span>c.<span>Loan I's monthly payment will be $11.88 smaller than Loan H's.</span></span>
X + (7 - 3i) + (5 + 9i) + 13i = 10 - 5i
Subtract 13i from both sides
x + (7 -3i) + (5 + 9i) = 10 - 18i
Subtract (5 + 9i). MAKE SURE YOU SUBTRACT 9i TOO. In other words, distribute the negative and subtract 5 and 9i at the same time.
x + (7 - 3i) = 5 - 27i
Do the same with (7 - 3i). You'll be adding 3i since -(-3i) = 3i.
x = -2 - 24i