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1 year ago

Answer my question pleaSE, I will give you brainlest!

Mathematics

2 answers:

Marina CMI [18]1 year ago

8 0

45=2x +x
X=number of friends the boy has
45=3x
45/3=15
x=15
The boy has 15 friends and the girl has 30 friends

Arlecino [84]1 year ago

4 0

Answer: 30

Step-by-step explanation: So clearly we want 45 to be divided into x and 2x. Because the sum of the two parts is 45, so x + 2x = 45 which gives us the value of x = 15.

So the boy has 15 while the girl has 30

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Sofia ordered sushi for a company meeting. They change plans and increase how many people will be at the meeting, so they need a

saveliy_v [14]

Answer:

Sofia will order 7 more rolls of sushi (84 pieces) and pay $56

Step-by-step explanation:

They need at least 100 pieces of sushi

Sofia had ordered and paid for 24 pieces of sushi already

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R=additional rolls that Sofia orders

Additional sushi= Needed sushi - ordered sushi

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=76 pieces of sushi

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Sofia has to order in rolls

So, she will order 7 more rolls of sushi of 12 pieces each

12*7=84 pieces

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She has paid for 24 pieces (3 rolls) at $8 per roll

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1 year ago

Read 2 more answers

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Answer:

Given that 1minute =3/7of the vessel

let the time taken in minutes to fill the whole of the vessel be' x' minute.

1min =3/7

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1 year ago

Harriet would like to frame her graduation picture. The picture is 8 inches wide and 11 inches long. She wants the total area of

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2 years ago

Sharon has some one-dollar bills and some five-dollar bills. She has 14 bills. The value of the bills is $30. Solve a system of

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Step-by-step explanation:

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1 year ago

A standard weight known to weigh 10 grams. Some suspect bias in weights due to manufacturing process. To assess the accuracy of

notsponge [240]

Answer:

a) The 98% confidence interval for the mean weight is between 10.00409 grams and 10.00471 grams

b) 49 measurements are needed.

Step-by-step explanation:

Question a:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.98}{2} = 0.01$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.01 = 0.99$ , so Z = 2.327.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 2.327\frac{0.0003}{\sqrt{5}} = 0.00031$

The lower end of the interval is the sample mean subtracted by M. So it is 10.0044 - 0.00031 = 10.00409 grams

The upper end of the interval is the sample mean added to M. So it is 10 + 0.00031 = 10.00471 grams

The 98% confidence interval for the mean weight is between 10.00409 grams and 10.00471 grams.

(b) How many measurements must be averaged to get a margin of error of +/- 0.0001 with 98% confidence?

We have to find n for which M = 0.0001. So

$M = z\frac{\sigma}{\sqrt{n}}$

$0.0001 = 2.327\frac{0.0003}{\sqrt{n}}$

$0.0001\sqrt{n} = 2.327*0.0003$

$\sqrt{n} = \frac{2.327*0.0003}{0.0001}$

$(\sqrt{n})^2 = (\frac{2.327*0.0003}{0.0001})^2$

$n = 48.73$

Rounding up

49 measurements are needed.

7 0

1 year ago