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Harlamova29_29 [7]
2 years ago
10

Glenna wants to rent a car for a trip to key west for one weekshe calls two car rental companies to get prices. mr kotters renta

ls rents a cadillac escalade for $99 for one week plus $0.11per mile over 100 miles. barbarino's rentals has the same vehicle for $75 per week and $0.15 per mile over 150 miles. if its 432 miles to key west, which company has the better deal? How many miles would Glenna drive before she would be spending the same amount at either company?
Mathematics
1 answer:
Korvikt [17]2 years ago
4 0

Answer: Barbarino's rentals has a better deal.

She has to drive 887.5 miles to spend the same amount at either company.

Step-by-step explanation:

Hi, to answer this question we have to analyze the information given:

<em>Mr.kotters rentals (A) </em>

  • <em>$99 PER WEEK </em>
  • <em>$0.11per mile over 100 miles </em>

<em>Barbarino's rentals (B) </em>

  • <em>$75 per week </em>
  • <em>$0.15 per mile over 150 miles </em>

For "A"

Cost = 0.11 (432-100) + 99 = $135.52

For "B"

Cost= 0.15 (432-150) +75 = $117.3

Barbarino's rentals has a better deal, since $117.3(B) < $135.52 (A)

To find how many miles would Glenna drive before she would be spending the same amount at either company:

A =B

0.11 (M-100) + 99 =0.15 (M-150) +75 = $117.3

Solving for M (miles)

0.11 M -11+99 = 0.15 M -22.5+75

-11 +99 +22.5 -75 =0.15M -0.11 M

35.5 = 0.04M

35.5/0.04 = M

887.5 =M

She has to drive 887.5 miles to spend the same amount at either company.

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Answer:

a) 90.695 lb

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Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 88, \sigma = 7

(a) The 65th percentile

X when Z has a pvalue of 0.65. So X when Z = 0.385.

Z = \frac{X - \mu}{\sigma}

0.385 = \frac{X - 88}{7}

X - 88 = 7*0.385

X = 90.695

(b) The 35th percentile

X when Z has a pvalue of 0.35. So X when Z = -0.385.

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X - 88 = 7*(-0.385)

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2 years ago
Find the 88th term of the arithmetic sequence 26, 28, 30,...
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Answer:

200

Step-by-step explanation:

Given Arithmetic sequence is: 26, 28, 30,...

First term a = 26

Common Difference d = 2

n = 88

\because t_n=a +(n-1) d \\  \therefore \: t_{88}=26 +(88-1)  \times 2 \\ \therefore \: t_{88}=26 +87  \times 2 \\ \therefore \: t_{88}=26 +174 \\ \huge \red{ \boxed{ \therefore \: t_{88}=200}} \\

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Number of stocks held = 30
Price at which each shares of Lofty Cheese Company bought = 20 1/4
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Price at which each shares of Lofty Cheese Company sold = 25 1/4
                                                                                             = (101/4) dollars
Amount of profit made per share of Lofty Cheese Company = [(101/4 - (81/4)] dollars
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So you will make a profit of $150.The correct option in regards to the question given is option "C".


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