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VMariaS [17]
2 years ago
8

This box has the same length , width, and height as the 2 basketballs. Which expression gives the volume of the empty space enci

rcling the basketballs inside the box?

Mathematics
2 answers:
Solnce55 [7]2 years ago
8 0
Don't you just grab the volume of the box and subtract the volume of the basketballs.
Vadim26 [7]2 years ago
4 0

Answer:

4,608(6- \pi)\ cm^{3}

Step-by-step explanation:

we know that

The volume of the empty space encircling the basketballs inside the box is equal to the volume of the box minus the volume of the two basketball inside the box

so

<u>The volume of the box is equal to</u>

V=LWH

in this problem we have

L=2*24=48\ cm

W=24\ cm

H=24\ cm

substitute

V=48*24*24=27,648\ cm^{3}

The volume of the two basketball inside the box is equal to

V=2*\frac{4}{3} \pi r^{3}

n this problem we have

r=24/2=12\ cm

substitute

V=\frac{8}{3} \pi 12^{3}

V=4,608 \pi\ cm^{3}

The expression is equal to

(27,648-4,608 \pi)\ cm^{3}

4,608(6- \pi)\ cm^{3}

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NB- Solution is emboldened

 

import java.util.Scanner;

import java.util.Random;

public class RandomGenerateNumbers {

public static void main (String [] args) {

Random randGen = new Random();

int seedVal = 0;

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4 0
2 years ago
Read 2 more answers
a ball is thrown with a slingshot at a velocity of 110ft/sec at an angle of 20 degrees above the ground from a height of 4.5 ft.
satela [25.4K]

Answer:

t=2.47\ s  

Step-by-step explanation:

The equation that models the height of the ball in feet as a function of time is

h(t) = h_0 + s_0t -16t ^ 2

Where h_0 is the initial height, s_0 is the initial velocity and t is the time in seconds.

We know that the initial height is:

h_0 = 4.5\ ft

The initial speed is:

s_0 = 110sin(20\°)\\\\s_0 = 37.62\ ft/s

So the equation is:

h (t) = 4.5 + 37.62t -16t ^ 2

The ball hits the ground when when h(t) = 0

So

4.5 + 37.62t -16t ^ 2 = 0

We use the quadratic formula to solve the equation for t

For a quadratic equation of the form

at^2 +bt + c

The quadratic formula is:

t=\frac{-b\±\sqrt{b^2 -4ac}}{2a}

In this case

a= -16\\\\b=37.62\\\\c=4.5

Therefore

t=\frac{-37.62\±\sqrt{(37.62)^2 -4(-16)(4.5)}}{2(-16)}

t_1=-0.114\ s\\\\t_2=2.47\ s  

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4 0
2 years ago
An internet service provider is implementing a new program based on the number of connected devices in each household. Currently
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The current rate is simply equal to $175 per month, let us call this as rate A:

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The new rate is $94 plus $4.50 per devices, let us call this as rate B:

B = 94 + 4.50 x

where x is the number of devices connected to the network

 

The inequality equation for us to find x which the new plan is less than current plan is:

94 + 4.50 x < 175

 

Solving for x:

4.50 x < 81

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So the number of devices must be less than 18.

 

 

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7 0
1 year ago
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levacccp [35]

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Edit: I just checked and it's definitely<u><em> ZERO</em></u>

7 0
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Answer:

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Thus, we have;

y = 15.261(8) + 8.83 = 122.088 + 8.83 = 130.918

This is approximately equal to 131

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2 years ago
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