#5: This graph shows the amount of gas, in ounces, in a lawn mower gas tank, modeled as a function of time. Determine whether ea
ch statement is true according to the graph. Select True or False for each statement.
Captionless Image
True False
The maximum amount of gas in the gas tank was 60 ounces.
The amount of gas in the gas tank is at a maximum at 0 minutes.
The gas tank will be empty after 60 minutes.
The maximum amount of gas in the gas tank was 60 ounces.
The amount of gas in the gas tank is at a maximum at 0 minutes.
The gas tank will be empty after 60 minutes.
Coupon
#6: John has a coupon for 20% off any item in a store. What would the final cost be for an item that originally cost $15 if he uses his coupon? (Assume there are no taxes)
Captionless Image
True False
The maximum amount of gas in the gas tank was 60 ounces.
The amount of gas in the gas tank is at a maximum at 0 minutes.
The gas tank will be empty after 60 minutes.
The maximum amount of gas in the gas tank was 60 ounces.
The amount of gas in the gas tank is at a maximum at 0 minutes.
The gas tank will be empty after 60 minutes.
Coupon
#6: John has a coupon for 20% off any item in a store. What would the final cost be for an item that originally cost $15 if he uses his coupon? (Assume there are no taxes)
2 answers:
Answer:
#5 False, True, True
#6 $12
Step-by-step explanation:
#5 In the figure attached, the missing picture is shown.
- The maximum amount of gas in the gas tank was 60 ounces. False, it was 30
- The amount of gas in the gas tank is at a maximum at 0 minutes. True
- The gas tank will be empty after 60 minutes. True
#6 The discount is equal to 20/100 * $15 = $3. Then, John has to pay $15 - $3 = $12
Answer:
5. See below
6. $12
Step-by-step explanation:
5.
<em>Image/Graph attached.</em>
<em />
<em>The maximum amount of gas in the gas tank was 60 ounces:</em>
The max amount is at the starting, at t = 0. The y-axis (amount of gas) at that time is at 30, so the max amount is 30, NOT 60.
False.
<em>The amount of gas in the gas tank is at a maximum at 0 minutes:</em>
This is true, because the more you drive, the less gas you have. You have a full tank/max before you start. That's at t = 0 minutes.
True.
<em>The gas tank will be empty after 60 minutes:</em>
The y-axis goes to 0 at t = 60 minutes. That means, after 60 minutes, gas is over. Tank is empty. So this is true.
True.
6.
If something costs $15 and John uses a coupon on that, he will get 20% off of that. The final price would be 20% (0.2) less than the original, $15. We need to find 20% of 15 and then subtract from 15.
20% of 15 = 0.2 * 15 = $3
Now
15 - 3 = $12
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Answer:
Step-by-step explanation:
Hello!
The variable is X: iron level on human blood.
It has a mean of μ= 51.50 mg/dl and a standard deviation of σ= 3.50 mg/dl.
According to the control chart, the process should be shut down for troubleshooting when the analysis shows values X[bar]≥ 53.42 mg/dl and X[bar]≤ 49.58 mg/dl
Warnings are received at levels X[bar]≥52.78 mg/dl and X[bar]≤ 50.22 mg/dl
The system works between levels 49.58<X[bar]<53.42 and works without warnings between 50.22<X[bar]<52.78.
Using these parameters you have to analyze if the lists of sample means to see which ones are within the working values are wich ones are outside this interval.
<u>Sample 1</u>
Min= 50.15
Max= 51.99
Mean= 51.61
Without warning 50.22<X[bar]<52.78
Without Action interval 49.58<X[bar]<53.42
<em>This sample's min value is below the lower limit of the warning interval but not low enough to reach action levels, the max value is within the working range.</em>
<em><u /></em>
<u>Sample 2 </u>
Min= 50.32
Max= 52.56
Mean= 51.16
Without warning 50.22<X[bar]<52.78
Without Action interval 49.58<X[bar]<53.42
<em>Both the max and min values of the sample are within the working range without warning.</em>
<em />
<u>Sample 3</u>
Min= 50.25
Max= 53.12
Mean= 51.83
Without warning 50.22<X[bar]<52.78
Without Action interval 49.58<X[bar]<53.42
<em>The max value of this sample is above the upper limit of the warning interval but does not surpass the upper bond of the troubleshoot interval. Min value is within working values.</em>
<em />
<u>Sample 4</u>
Min= 50.05
Max= 53.01
Mean= 51.70
Without warning 50.22<X[bar]<52.78
Without Action interval 49.58<X[bar]<53.42
<em>Both min and max values surpass the warning interval but do not reach action levels</em>.
<u>Sample 5</u>
Min= 50.35
Max= 52.71
Mean= 51.37
Without warning 50.22<X[bar]<52.78
Without Action interval 49.58<X[bar]<53.42
<em>Both min and max values are within working levels without warnings.</em>
<em />
Considering that samples reaching warning levels should be shut down as a precaution, they are classified as:
Shutdown: Sample 1, 3 and 4
Do not shutdown: Sample 2 and 5.
I hope it helps!
Answer: 3 million barrels
Step-by-step explanation:
Given :- Total crude oil= 60 million barrels
Quantity of gasoline = 34% of total crude oil
Quantity of diesel = 29% of total crude oil
Clearly, Quantity of gasoline is more than Quantity of diesel
difference = Quantity of gasoline-Quantity of diesel
Therefore, The production of gasoline is 3 million barrels more than diesel last year.