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Dimas [21]
2 years ago
7

Point A is the midpoint of side XZ and point B is the

Mathematics
1 answer:
Katyanochek1 [597]2 years ago
6 0

Answer:

Option (2)

Step-by-step explanation:

Given question is incomplete; here is the complete question.

Point A is the midpoint of side XZ and point B is the  midpoint of side YZ.

Triangle XYZ is cut by line segment AB. Point A is the midpoint of side XZ and point B is the midpoint of side YZ. The length of XY is (5x - 7), the length of AB is (x + 1), and the lengths of XA and ZA are (2x - 2). The lengths of YB and BZ are congruent.

What is AX ?

2 units

4 units

6 units

8 units

From the figure attached,

XYZ is a triangle having A and B as the midpoints of the sides XZ and YZ.

By the theorem of midpoints,

AB = \frac{1}{2}\text{(XY)}

Since AB = (x + 1) and XY = (5x - 7)

(x + 1) = \frac{1}{2}(5x-7)

2x + 2 = 5x - 7

5x - 2x = 2 + 7

3x = 9

x = 3

Therefore, side AB = 3 + 1 = 4 units

Side XY = (5x - 7)

             = 15 - 7

             = 8 units

Side XA = 2(x - 1)

              = 4 units

Therefore, Option (2) will be the answer.

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Tiffany is monitoring the decay of two radioactive compounds in test tubes at her lab. Compound A is continuously decaying at a
trapecia [35]

Answer:

30e-0.12t

40e-0.18t

Step-by-step explanation:

6 0
2 years ago
Mike has coffee worth $4 per pound that he wishes to mix with 20 pounds of coffee worth $7 per pound to get a mixture that can b
Alinara [238K]
\bf \begin{array}{lccclll}
&\stackrel{lbs}{amount}&\stackrel{per~lb}{price}&\stackrel{amount}{price}\\
&------&------&------\\
\textit{\$4/lb coffee}&x&4&4x\\
\textit{\$7/lb coffee}&20&7&140\\
------&------&------&------\\
mixture&y&5&5y
\end{array}

so, we know the mixture is the sum of both types of coffee, thus x + 20 = y, and 4x + 140 = 5y.

\bf \begin{cases}
x+20=\boxed{y}\\
4x+140=5y\\
----------\\
4x+140=5\left( \boxed{x+20} \right)
\end{cases}
\\\\\\
4x+140=5x+100\implies 140-100=5x-4x\implies 40=x
5 0
1 year ago
What values of b satisfy 3(2b + 3)2 = 36?
meriva
What values of b satisfy 3(2b+3)^2 = 36

we have
3(2b+3)^2 = 36
Divide both sides by 3
(2b+3)^2 = 12
take the square root of both sides
( 2b+3)} =(+ /-) \sqrt{12} \\ 2b=(+ /-) \sqrt{12}-3

b1=\frac{\sqrt{12}}{2} -\frac{3}{2}
b1=\sqrt{3} -\frac{3}{2}

b2=\frac{-\sqrt{12}}{2} -\frac{3}{2}
b2=-\sqrt{3} -\frac{3}{2}
therefore

the answer is
the values of b are
b1=\sqrt{3} -\frac{3}{2}
b2=-\sqrt{3} -\frac{3}{2}
9 0
1 year ago
1. Lisa and Tomas Lopez are buying a new minivan that has a base
Dimas [21]

The question is incomplete:

Lisa and Tomas Lopez are buying a new minivan that has a base price of $22,510.the options total $8,062 and destination charge is $770. The dealer's cost is estimated to be 91% of the base price and 88% of the options.

-What is the sticker price of the vehicle?

-Find the dealer's percent of the base price.

-Find the dealer's percent of the options price.

-What is the estimated dealer's cost?

Answer:

-What is the sticker price of the vehicle? $31,342

-Find the dealer's percent of the base price: $20,484

-Find the dealer's percent of the options price: $7,094

-What is the estimated dealer's cost?  $28,348

Step-by-step explanation:

-The sticker price is the result of adding the base price plus the options plus the destination charge.

Sticker price= base price + options + destination charge

Sticker price= $22,510+$8,062+$770

Sticker price= $31,342

-Dealer's percent of the base price: It is  91% of the base price:

$22,510*91%= $20,484

-Dealer's percent of the options price: It is  88% of the options:

$8,062*88%= $7,094

-Estimated dealer's cost= Percent of base price+percent of options price+destination charge

Estimated dealer's cost= $20,484+$7,094+$770

Estimated dealer's cost=$28,348

4 0
2 years ago
Suppose the supply function for product x is given by qxs = - 30 + 2px - 4pz.
Igoryamba

It is given in the question that

Suppose the supply function for product x is given by

qxs = - 30 + 2px - 4pz.

And we have to find how much of product x is produced when px = $600 and pz = $60.

And for that, we have to substitute 600 for px and 60 for pz, and on doing so, we will get

qxs = -30+2(600)-4(60)
\\
qxs = -30 +1200 -240 = 930

And that's the required answer .

3 0
2 years ago
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