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zloy xaker [14]

1 year ago

11

Which value of x would make LK ∥ OM? x = 2 x = 2.4 x = 4.8 x = 8

1 answer:

goldenfox [79]1 year ago

6 0

Answer:

x=8

Step-by-step explanation:

The figure is shown in the attached figure.

We have, LK║OM. We need to find the value of x.

It is based on side-splitter theorem. If a line is parallel to third side of a triangle, then the points that intersects the two lines, it divides proportionally.

Using it in given problem. So,

$\dfrac{\text{NK}}{\text{KM}}=\dfrac{\text{NL}}{\text{LO}}$

Nk = x+2, KM = x-3, NL = x and LO = x-4

So,

$\dfrac{x+2}{x-3}=\dfrac{x}{x-4}$

Cross multiplying, we get :

$(x+2)(x-4)=x(x-3)\\\\x^2-4x+2x-8=x^2-3x\\\\-2x+3x=8\\\\x=8$

So, the value of x is 8.

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What is the perimeter of the trapezoid with vertices Q(8, 8), R(14, 16), S(20, 16), and T(22, 8)? Round to the nearest hundredth

uysha [10]

Answer:

The perimeter of the trapezoid is $38.25\ units$

Step-by-step explanation:

we know that

The perimeter of the trapezoid is the sum of its four side lengths

so

In this problem

$P=QR+RS+ST+QT$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

$Q(8, 8), R(14, 16), S(20, 16),T(22, 8)$

step 1

Find the distance QR

$Q(8, 8), R(14, 16)$

substitute the values in the formula

$d=\sqrt{(16-8)^{2}+(14-8)^{2}}$

$d=\sqrt{(8)^{2}+(6)^{2}}$

$d=\sqrt{100}$

$QR=10\ units$

step 2

Find the distance RS

$R(14, 16), S(20, 16)$

substitute the values in the formula

$d=\sqrt{(16-16)^{2}+(20-14)^{2}}$

$d=\sqrt{(0)^{2}+(6)^{2}}$

$d=\sqrt{36}$

$RS=6\ units$

step 3

Find the distance ST

$S(20, 16),T(22, 8)$

substitute the values in the formula

$d=\sqrt{(8-16)^{2}+(22-20)^{2}}$

$d=\sqrt{(-8)^{2}+(2)^{2}}$

$d=\sqrt{68}$

$ST=8.25\ units$

step 4

Find the distance QT

$Q(8, 8),T(22, 8)$

substitute the values in the formula

$d=\sqrt{(8-8)^{2}+(22-8)^{2}}$

$d=\sqrt{(0)^{2}+(14)^{2}}$

$d=\sqrt{196}$

$QT=14\ units$

step 5

Find the perimeter

$P=10+6+8.25+14=38.25\ units$

6 0

2 years ago

Read 2 more answers

Which expression is equivalent to the expression below? StartFraction m + 3 Over m squared minus 16 EndFraction divided by Start

Kamila [148]

Option B: $\frac{1}{(m-4)(m-3)}$ is the correct answer.

Explanation:

The given expression is $\frac{(\frac{m+3}{m^2-16}) }{(\frac{m^2-9}{m+4} )}$

Simplifying the expression, we have,

$\frac{m+3}{m^{2}-16}\times\frac{m+4}{m^2-9}$

Factor the equations, $m^{2}-16\right$ and $m^{2}-9$ ,we get,

$m^{2}-16\right=m^{2}-4^{2}=(m+4)(m-4)$

$m^{2}-9=m^{2}-3^2=(m+3)(m-3)$

Substituting these factored expressions in the above expression, we have,

$\frac{m+3}{(m+4)(m-4)}\times\frac{m+4}{(m+3)(m-3)}$

Cancelling the common terms $m+3$ and $m+4$ , we get,

$\frac{1}{(m-4)(m-3)}$

Thus, the expression equivalent to $\frac{(\frac{m+3}{m^2-16}) }{(\frac{m^2-9}{m+4} )}$ is $\frac{1}{(m-4)(m-3)}$

Hence, Option B is the correct answer.

3 0

1 year ago

Read 2 more answers

How is (s-t)(s/t) equivalent to (s^2/t) -s

tigry1 [53]

$(s-t)\cdot\dfrac{s}{t}=s\cdot\dfrac{s}{t}-t\cdot \dfrac{s}{t}=\dfrac{s^2}{t}-s$

4 0

1 year ago

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Kevin and Brittany write an equation to represent the following relationship, and both students solve their equation. Who found

Vadim26 [7]

Kevin, because the problem says the difference of a number (x) and 20, and since 20 is mentioned second, it would therefore be the second number in the problem

3 0

1 year ago

Bob Rohrman is offering a 2016 Toyota Camry for $29,000. If you have a $5,000 down payment and are able to borrow the rest at a

vova2212 [387]

Answer:

The monthly payment will be $531.12

Step-by-step explanation:

Consider the provided information.

After paying $5,000 down payment you need to pay:

$29,000-$5,000=$24,000

APR is 2.99% or APR = 0.299%

Therefore, $r=\frac{0.0299}{12}$

n = 48

We can calculate the monthly payment by using the formula:

$P=\frac{r(PV)}{1-(1+r)^{-n}}$

Where P is the monthly payment, PV is the present value, r is the rate per period and n is the number of period.

Substitute the respective values in the above formula we get,

$P=\frac{\frac{0.0299}{12}(24000)}{1-(1+\frac{0.0299}{12})^{-48}}$

$P=\frac{59.8}{0.112593}$

$P\approx531.12$

Hence, the monthly payment will be $531.12

4 0

1 year ago