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KATRIN_1 [288]
2 years ago
14

{(–9, 1), (–5, 2), (0, 7), (1, 3), (6, –10)} Josiah claims that the ordered pair (6, –10) can be replaced with any ordered pair

and the set will still represent a function. Select all ordered pairs that could be used to show that this claim is incorrect.
A. (–10, –10)
B. (–9, –6)
C. (–5, 1)
D. (1, 12)
E. (4, 7)
Mathematics
1 answer:
Scrat [10]2 years ago
6 0
<span>B. (–9, –6) 
</span><span>C. (–5, 1) 
D. (1, 12) 

Remember that no two x's can be the same in a function.</span>
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Find H.C.F. and L.C.M. of x3-y3, x2-y2 and (x-y) ?​
maks197457 [2]

Answer:

1) x³-y³ = (x-y)(x²-xy+y²)

2)x²-y² =(x-y)(x+y)

3)x-y = (x-y)

hcf = (x-y)

lcm = (x-y)(x²-xy+y²)(x+y)= (x³-y³)(x+y)

Step-by-step explanation:

5 0
2 years ago
Apples: $(2x) per pound
Ludmilka [50]

Answer:

Shopper spend $3 on Apples, $4 on Grapes and $3.5 on Oranges

Step-by-step explanation:

Cost of one pound of Apple = $2x

Cost of one pound of Grapes = $(6x-5)

Cost of one pound of Oranges = $(x+2)

A shopper purchases one pound each of  apples, grapes, and oranges and spends  $10.50.

It can be written as: 2x+6x-5+x+2=10.50

We need to find how much the shopper spend on each fruit.

First we need to find value of x by solving equation

2x+6x-5+x+2=10.50

Solving:

2x+6x+x+2-5=10.50\\9x-3=10.50\\9x=10.50+3\\9x=13.5\\x=\frac{13.5}{9}\\x=1.5

The value of x is: x=1.5

Now finding cost of one pound each fruit by putting x=1.5

Cost of one pound of Apple = $2x = 2(1.5) = $3

Cost of one pound of Grapes = $(6x-5) = (6(1.5)-5)= $4

Cost of one pound of Oranges = $(x+2)=(1.5+2)=$3.5

So,

Cost of one pound of Apple  = $3

Cost of one pound of Grapes = $4

Cost of one pound of Oranges = $3.5

So, shopper spend $3 on apples, $4 on Grapes and $3.5 on Oranges

3 0
2 years ago
One of the assumptions underlying the theory of control charting is that successive plotted points are independent of one anothe
aksik [14]

Answer:

P(at least 1 wrong in 10) =0.5160

Step-by-step explanation:

Let A be the event  that there is a problem in the proces. Then the probability of problem with the process is P ( A) = 0.07

Let B be the event  that the process is without the problem. Then the probability of without problem is P ( B) = 0.93

Now we want to find the 10 successive points of event B. Since the events are independent we can find this as

P(B)+P(B)+P(B)+P(B)+P(B)+P(B)+P(B)+P(B)+P(B)+P(B)

or

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4 0
2 years ago
Tony’s class needs more than $500 for the school dance. So far, they have raised $200. They plan to have a car wash, charging $8
Orlov [11]

Answer: no Tony is not correct It is less than 5 hundred dollars.

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4 0
2 years ago
Read 2 more answers
A pond had 60 fish. 27 were carp and the rest were tench. 10 fish were added. The probability that a fish picked at random is a
ivanzaharov [21]

Answer: 2

<u>Explanation:</u>

A pond had 60 fish but 10 were added so now the pond has 70 fish.

The probability of choosing a carp is 1/2 so \frac{1}{2} (70) = 35 are now carp.  

There were 27 carp and now there are 35 carp so 8 carp were added.

10 fish were added and 8 of them were carp so 2 of them were tench.

6 0
2 years ago
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