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Shkiper50 [21]
2 years ago
11

Helppppppppppppppppppppp failingggggggggggggggg quizzzzzzzzzzzzzzzzzzzzzzzzzzzz

Mathematics
2 answers:
vladimir1956 [14]2 years ago
4 0

Answer: 1.If two quadrilaterals are congruent, then there must be <u>4 </u>pairs of corresponding sides.    [C<u>)</u> is true]

2. Statement  ∆KPT ≅ ∆KRT.                       [D) is true.]

3. If CDEF ≅ MNPQ, then ∠P ≅ <u>∠E</u>                   <u>[C) is true.]</u>

4. If ∆LMC ≅ ∆BJK, then  <u>∆MCL</u> ≅ ∆JKB.    [B) is true.]

5. If ABCDE ≅ LMNPQ, then  there are 10 pairs of corresponding parts .

6.  If ∠C ≅ ∠​M, ∠E ≅ ∠​Q, ED, ≅ QN,CD ≅MN and EC≅QM , then <u>∆CED </u>≅∆MQN             [A)<u>  is true</u>]

7. ∠B and ∠E​  will be a pair of corresponding parts if ∆ABC ≅ ∆DEF.     [B) is true.]

8. B) is true.∆QPR ≅ ∆SPR

.   [B) is true]

9. If two angles of one triangle are congruent to two angles of another triangle, then the <u>third angles</u> are congruent.    [C) is true.]

10. If CDEF ≅ MNPQ, then ∠N ≅ ∠D.   [C) is true.]





Kaylis [27]2 years ago
3 0
I'm not positive on the first one but I believe it's all four sides.

2) KPT and KRT. when stating congruence the order must be the same. in this case the start and end of the triangle is the same (K, and T)
3) C. :E, The letter placement matches. in number two P is congruent to R.
4) B. if you start at the top (J) then to find the other triangle you must also start at the top. it goes from J to K. so on the other triangle you must also go the short leg first so M to C. then finish it off.
5)D. if one triangle has LMNPQ, then there are five letters so five parts. the other triangle is congruent and also has five letters and five parts. so there are five congruent parts
6)D. its asking for the triangle congruent to MQN. it says C and N are equal and N is at the end of the order so the congruent triangle must have C at the end of the order.E and Q are congruent and Q is in the middle so E must also me in the Middle. the only option is DEC
7) B this test really makes you focus on placement. in the congruent statement the E and B and both in the middle and therefore pair up together
8)B. again, if you start with the angle that is congruent in one order then its needs to happen for the other order. Then they both follow down the congruent side with 1 tally and finish it off with the side they both share.
9) I'm thinking its "triangles" it sounds like AAS or AAA congruency

As a side note for a lot of these just remember CPCTC. Corresponding Parts of Congruent Triangles are Congruent

Finally 10)C. CPCTC. its all about order
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In a statewide soccer competition, 36 games were played. Each team participating in the competition played once with every other
Tomtit [17]

Answer:

9 teams

Step-by-step explanation:

If the total games played was 36 and no team played each other twice, we need to ensure there isn't any double counting.

36 = (n-1) + (n-2) + (n-3) ... + (n-(n-1))

using this knowledge, we can then count up:

1+2+3+4+5+6+7+8 = 36

If our highest number is 8, then we know there must be 9 teams, because no team can play themselves.

8 0
2 years ago
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Kali left school and traveled toward her friend’s house at an average speed of 40
ioda
Matt needs to travel 3 hours. 
If 40km=1 hour
   400km=? But there are two distances
200/40*1=5 hours
Therefore Kali needs to travel 5 hours to be 200 km away from the house.
If 50km=1 hour
200km=?
200/50*1hr=4hrs Therefore Matt needs to travel 4hrs to be 200 km away from the house. But Kali traveled 1hr earlier than Matt. 4hrs-1hr=3hrs
Therefore Matt has to travel for 3 hours to be 400km away from Kali.
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2 years ago
The orbit of the planet Venus is nearly circular. An astronomer develops a model for the orbit in which the sun has coordinates
klio [65]
Since the Venus orbits round the sun, the sun is the center of the circular path of the revolution of the planet, Venus.

Thus, the distance of the planet, Venus fron the sun is given by the distance between the points (0, 0) and (41, 53).

Recall that the distance between two points (x_1, y_1) and (x_2, y_2) is given by d= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Thus, the distance between the points (0, 0) and (41, 53) is given by:

d= \sqrt{(41-0)^2+(53-0)^2}  \\  \\ = \sqrt{41^2+53^2} = \sqrt{1,681+2,809}  \\  \\ = \sqrt{4,490} =67 \ units

Given that each unit of the plane represents 1 million miles, therefore, the distance from the sun to the Venus is 67 million miles.
8 0
2 years ago
If a(x) = 3x + 1 and b (x) = StartRoot x minus 4 EndRoot, what is the domain of (b circle a) (x)?
kiruha [24]

Answer:

[1,\infty)

Step-by-step explanation:

b(x)=\sqrt{x-4}

a(x)=3x+1

Since we want to know the domain of (b \circ a)(x), let's first consider the domain of the inside function, that is, that of a(x)=3x+1. Every polynomial function has domain all real numbers.

So we can plug anything for function a and get a number back.

Now the other function is going to be worrisome because it has a square root. You cannot take square root of negative numbers if you are only considering real numbers which that is the case with most texts.

Let's find (b \circ a)(x) and simplify now.

(b \circ a)(x)

b(a(x))

b(3x+1)

\sqrt{(3x+1)-4}

\sqrt{3x+1-4}

\sqrt{3x-3}

Now again we can only square root positive or zero numbers so we want 3x-3 \ge 0.

Let's solve this to find the domain of (b \circ a)(x).

3x-3 \ge 0

Add 3 on both sides:

3x \ge 3

Divide both sides by 3:

x \ge 1

So we want x to be a number greater than or equal to 1.

The option that says this is [1,\infty)

-------------------------------

Give an example why option A fails:

A number in the given set is -2.

a(x)=3x+1

b(x)=\sqrt{x-4}

So a(-2)=3(-2)+1=-6+1=-5 and b(-5)=\sqrt{-5-4}=\sqrt{-9} \text{ which is not real}.

Give an example why option B fails:

A number in the given set is 0.

a(x)=3x+1

b(x)=\sqrt{x-4}

So a(0)=3(0)+1=0+1=1 and b(1)=\sqrt{1-4}=\sqrt{-3} \text{ which is not real}.

Give an example why option D fails:

While all the numbers in set D work, there are more numbers outside that range of numbers that also work.

A number not in the given set that works is 3.

a(x)=3x+1

b(x)=\sqrt{x-4}

So a(3)=3(3)+1=9+1=10 and b(1)=\sqrt{10-4}=\sqrt{6} \text{ which is real}.

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2 years ago
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Corinne and Aretha are having a 26-mile race. Corinne gave Aretha a head start by letting her begin 3.5 miles in front of the st
Ronch [10]
From the table, the speed of Corinne is given by

speed=slope= \frac{2.5-1.25}{20-10} = \frac{1.25}{10} =0.125 \ miles / minute

From the graph, the speed of Aretha is given by

speed=slope= \frac{5.5-4.5}{20-10} = \frac{1}{10} =0.1 \ miles / minute

The distance from the starting point of Corinne at any time t is given by D = 0.125t while the distance from the starting point of Aretha at any time t is given by D = 3.5 + 0.1t

Let t be the number of minutes after the start of the race when Corinne catchs Aretha, then

0.125t = 3.5 + 0.1t
0.025t = 3.5
t = 3.5 / 0.025 = 140

Therefore, the number of <span>minutes after the start of the race that Corinne will catch Aretha</span> is 140 minutes.
6 0
2 years ago
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