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2 years ago

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a school conducts 27 test in 36 weeks. assume the school conducts tests at a constant rate .what is the slope of the line that r

epresents the number of tests on the y-axis and the time in weeks on the x- axis

2 answers:

nevsk [136]2 years ago

4 0

The slope of a graph is base on the rise over run of the line connected by the points which composed of an X and Y coordinate. The rise of the line is its Y and the Run is X. Base on the assigning of variables of its x and y value, the slope is calculate by dividing the weeks by its test so the answer is 3 over 4 or 0.75

Brilliant_brown [7]2 years ago

3 0

Answer: Slope of the line = 0.75.

Step-by-step explanation:

Since we have given that

Number of tests = 27

Number of weeks = 36

According to question,

Number of tests is on the y-axis and the time in weeks is on the x-axis.

So, the coordinates are the (0,27) and (36,0)

As we know the formula for "Slope of line":

$m=\frac{y_2-y_1}{x_2-x_1}\\\\m=\frac{27-0}{36-0}\\\\m=\frac{27}{36}\\\\m=\frac{3}{4}\\\\m=0.75$

Hence, Slope of the line = 0.75.

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2 years ago

Express f(x) = |x-2| +|x+2| in the non-modulus form. Hence, sketch the graph of f.

alexgriva [62]

Recall that

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$|x-2|+|x+2|=-(x-2)-(x+2)=-2x-4$

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2 years ago

What is 10.2719 rounded to the nearest hundreth?

Paladinen [302]

Find the number in the hundredth place
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2 years ago

Read 2 more answers

Jackie bought a 3-pack of tubes of glue. She used 0.27 ounce of the glue from the 3-pack

adell [148]

This question is not correct because one of its options was not written correctly.

Correct question:

Jackie bought a 3-pack of tubes of glue. She used 0.27 ounce of the glue from the 3-pack

and had 1.35 ounces left in total. Which describes a way to determine the number of ounces

sold in each tube of glue?

a) Solve for x in the equation 3x - 0.27 = 1.35.

b) Divide 1.35 by 3 and then subtract 0.27 from the quotient.

c) Subtract 0.27 from 1.35 and the divide the difference by 3.

d) Solve for w in the equation 3 (x - 0.27) = 1.35.

Answer:

a) Solve for x in the equation 3x - 0.27 = 1.35.

Step-by-step explanation:

From the question we are told that 0.27 ounces of glue was sold from a 3 pack glue and we have 1.35 ounces of glue left in total.

The first step would be represent the 3 pack of glue as 3x where x represents each pack of the glue.

Therefore, mathematically, we have the Algebraic equation:

3x - 0.27 = 1.35..... Equation 1

This is because when we solve for x, we would be able to find the number of ounces sold in each tube.

Solving for x in the equation 3x - 0.27 = 1.35.

3x - 0.27 = 1.35.

3x = 1.35 + 0.27

3x = 1.62 ...... Equation 2

3x = The three pack tube containing the glue.

Where x represents each of the tubes.

This means, the three pack tube contained 1.62 ounces of glue.

To find out he amount of glue sold from each pack, we go back to our equation 2

3x = 1.62

x = 1.62 ÷ 3

x = 0.54 ounces.

This means from each tubes, 0.54 ounces of glue was sold.

Therefore, Option a) "Solve for x in the equation 3x - 0.27 = 1.35" is correct.

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2 years ago

A member of a student team playing an interactive marketing game received the fol- lowing computer output when studying the rela

nirvana33 [79]

Answer:

$p_v = 2*P(t_{n-2} > |t_{calc}|)= 0.91$

So on this case for the significance level assumed $\alpha=0.05$ we see that $p_v >\alpha$ so then we can conclude that the result is NOT significant. And we don't have enough evidence to reject the null hypothesis.

So on this case is not appropiate say that :"the more we spend on advertising this product, the fewer units we sell" since the slope for this case is not significant.

Step-by-step explanation:

Let's suppose that we have the following linear model:

$y= \beta_o +\beta_1 X$

Where Y is the dependent variable and X the independent variable. $\beta_0$ represent the intercept and $\beta_1$ the slope.

In order to estimate the coefficients $\beta_0 ,\beta_1$ we can use least squares procedure.

If we are interested in analyze if we have a significant relationship between the dependent and the independent variable we can use the following system of hypothesis:

Null Hypothesis: $\beta_1 = 0$

Alternative hypothesis: $\beta_1 \neq 0$

Or in other words we want to check is our slope is significant (X have an effect in the Y variable )

In order to conduct this test we are assuming the following conditions:

a) We have linear relationship between Y and X

b) We have the same probability distribution for the variable Y with the same deviation for each value of the independent variable

c) We assume that the Y values are independent and the distribution of Y is normal

The significance level assumed on this case is $\alpha=0.05$

The standard error for the slope is given by this formula:

$SE_{\beta_1}=\frac{\sqrt{\frac{\sum (y_i -\hat y_i)^2}{n-2}}}{\sqrt{\sum (X_i -\bar X)^2}}$

Th degrees of freedom for a linear regression is given by $df=n-2$ since we need to estimate the value for the slope and the intercept.

In order to test the hypothesis the statistic is given by:

$t=\frac{\hat \beta_1}{SE_{\beta_1}}$

The p value on this case would be given by:

$p_v = 2*P(t_{n-2} > |t_{calc}|)= 0.91$

So on this case for the significance level assumed $\alpha=0.05$ we see that $p_v >\alpha$ so then we can conclude that the result is NOT significant. And we don't have enough evidence to reject the null hypothesis.

So on this case is not appropiate say that :"the more we spend on advertising this product, the fewer units we sell" since the slope for this case is not significant.

3 0

2 years ago