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4vir4ik [10]
1 year ago
11

A paper company needs to ship paper to a large printing business. The paper will be shipped in small boxes and large boxes. The

volume of each small box is 7 cubic feet and the volume of each large box is 13 cubic feet. There were twice as many large boxes shipped as small boxes shipped and the total volume of all boxes was 165 cubic feet. Determine the number of small boxes shipped and the number of large boxes shipped.
Mathematics
1 answer:
Molodets [167]1 year ago
6 0

Answer:

small boxes = 5 and large boxes = 10

Step-by-step explanation:

Given:

The volume of each small box is 7 cubic feet.

volume of each large box is 13 cubic fee.

There were twice as many large boxes shipped as small boxes shipped.

Total volume of all boxes was 165 cubic feet.

Question asked:

The number of small boxes shipped and the number of large boxes shipped?

Solution:

Let  number of small boxes shipped = x

Then, the number of large boxes shipped = 2x (given)

Total volume of all boxes = 165 cubic feet.

no. of small boxes \times vol. of each small box +  no. of large boxes \times vol. of each large box =  165 cubic feet. (Total volume of all boxes)

x \times7 + 2x \times 13 = 165\\7x + 26x = 165\\33x = 165

Dividing both side by 33

x = \frac{165}{33}\\ x = 5

The number of small boxes shipped = x = 5

The number of large boxes shipped = 2 x = 2\times 5 = 10

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​You'd like to estimate the proportion of the 12,152 full-time undergraduate students at a university who are foreign students.
Minchanka [31]

Answer:

a) The data distribution consists of ( 7 )​1's (denoting a foreign ​student) and ( 43 )0's (denoting a student from the​ U.S.).

b) The population distribution consists of the​ x-values of the population of 12,152 full-time undergraduate students at the​university, ( 6 )​% of which are​ 1's (denoting a foreign​ student) and ( 94 )% of which are​ 0's (denoting a student from the​ U.S.).

c) The mean is ( 0.06 )

The standard deviation is ( 0.0336 )

The sampling distribution represents the probability distribution of the ( sample ) proportion of foreign students in a random sample of ( 50 ) students. In this​ case, the sampling distribution is approximately normal with a mean of ( 0.06 ) and a standard deviation of ( 0.0336 )

Step-by-step explanation:

5 0
2 years ago
Line l has a slope of 2. The line through which of the following pair of points is perpendicular to l?
djverab [1.8K]

Answer:

D

Step-by-step explanation:

If two lines are perpendicular, the products of their slopes will be -1. Therefore, we're looking for a line with slope of -1/2. Let's check each answer:

A: 5 - 3 / (-2 - 3) = 2 / -5    

B: 6 - 5 / 6 - 5 = 1

C: 5 - 3 / 4 - 3 = 2

D: 4 - 3 / 3 - 5 = -1/2

The answer is D.

8 0
2 years ago
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In a shipment of toys from a manufacturer. The probability that a toy is defective is 1/50. If Marie selects 2 toys from a shipm
sukhopar [10]
The probability is 1/2500. (1/50)*(1/50)
7 0
2 years ago
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Joshua started cycling at 5:15 pm By 8:09 pm, he has covered a distance of 7250 mWhat was Joshua's average speed during that tim
vivado [14]

The average speed of Joshua during that time is 2500 m/h.

Explanation:

It is given that Joshua started cycling at 5:15 pm. By 8:09 pm he has covered a distance of 7250 m.

The total time taken by Joshua from 5:15 pm to 8:09 pm is

2 { h } 54 \text { min }=2 \mathrm{h}+\frac{54}{60} {h}

Dividing we get,

2 { h } 54 \text { min }=2 \mathrm{h}+0.9 {h}

Adding, we have,

2 { h } 54 \text { min }=2.9 {h}

Thus, the total time taken by Joshua is 2.9 {h}

To determine the average speed we use the formula,

speed=\frac{distance}{time}

where distance=7250 and time=2.9

Hence, substituting the values we have,

speed=\frac{7250}{2.9}

Dividing, we get,

speed=2500

Thus, the average speed of Joshua during that time is 2500 m/h.

5 0
2 years ago
100 POINTS AND BRAINLIYEST!!!
Helga [31]

See explanations below

Step-by-step explanation:

Chanel

(i) 90° counterclockwise and then dilation by a factor of 1/2

Trapezoid PQRS is given as :

P(6,-4) -------P'(4,6)

Q(2,-2)------Q'(2,2)

R(2,-6)-------R'(6,2)

S(6,-6)-------S'(6,6)

The transformation switches the position of (x,y) to and adds a -ve sign to the original y value

B. The new coordinates are : P'(4,6), Q'(2,2),R'(6,2) and S'(6,6)

The  rule for rotation 90° counterclockwise about the origin is (x,y)⇒(-y,x)

The rule for dilation with scale factor of 1/2 is (x,y)------(1/2x,1/2y)

P'(4,6) -----P''(2,3)

Q'(2,2)-----Q''(1,1)

R'(6,2)-----R''(3,1)

S'( 6,6)-----S''(3,3)

The dilation reduces the coordinates by 1/2

Preston

E. (i)Reflection over x-axis where the rule is : (x,y)----(x,-y)

(ii)Dilation by scale factor of 1/2 the rule is : (x,y)---(1/2x, 1/2y)

Applying reflection over x-axis rule;

P(6,-4) -----P'(6,4)

Q(2,-2)-----Q'(2,2)

R(2,-6)------R'(2,6)

S(6,-6)------S'(6,6)

The coordinates have changed in that a negative sign is added to the y-axis coordinate.

F. P'(6,4), Q'(2,2), R'(2,6) and S'(6,6)

G. Applying the dilation by scale factor of 1/2

P'(6,4)-------P''(3,2)

Q'(2,2)------Q''(1,1)

R'(2,6)------R''(1,3)

S'(6,6)------S''(3,3)

The coordinates of P'Q'R'S are divide by 2 to give coordinates of P''Q''R''S''

Comparing the answers to the final figure given

K(3,2)

L(1,1)

M(1,3)

N(3,3)

Preston is correct because his sequence proves trapezoid PQRS is similar to trapezoid KLMN.

Learn More

Reflection and dilation :brainly.com/question/13408902

Keywords :trapezoid, maps, rotate, counterclockwise, dilate,reflect,scale factor,shape, coordinate

#LearnwithBrainly

4 0
2 years ago
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