(9,40,41) is a Pythagorean Triple, farther down the list than teachers usually venture.
Answer: D. 41 cm
There's a subset of Pythagorean Triples where the long leg is one less than the hypotenuse,
a^2+b^2 = (b+1)^2
a^2 + b^2 = b^2 + 2b +1
a^2=2b+1
So we get one for every odd number, since the square of an odd number is odd and the square of an even number is even.
b = (a^2 - 1)/2
a=3, b=(3^2-1)/2=4, c=b+1=5
a=5, b=(5^2-1)/2 =12, c = 13
a=7, b=24, c=25
a=9, b=40, c=41
a=11, b=60, c=61
a=13, b=84, c=85
It's good to be able to recognize Pythagorean Triples when we see them.
Otherwise we'd have to work the calculator:
√(9² + 40²) = √1681 = 41
Answer:
see below
Step-by-step explanation:
Since we replace the marble , we can draw the same color again
yy oo ro
yo oy ry
yr or rr
There are 9 possible outcomes for drawing 2 marbles
5 of them have at least one yellow marble
545,999 rounded to the nearest hundred thousand is 546,000.
For this case we have that by definition, the area of a triangle is given by:
Where:
b: It is the base of the triangle
h: It is the height of the triangle
According to the statement data we have:
Substituting we have:
We divide between 2 on both sides:
We factor by looking for two numbers that, when multiplied, are obtained -88 and when added together, +3 is obtained.
These numbers are +11 and -8.
We have two roots:
We choose the positive value.
Thus, the base of the triangle is:
Answer:
The base of the triangle is 22 units.
The formula for solving the problem is as follow:
an = a1 + (n - 1)d
Where:
n = number of figure in the sequence = 4
d = difference between successive number =?
a1 = -1
a4 = 59
Insert the given values into the formula,
59 = -1 + (4 - 1)d
59 = -1 + 3d
59 + 1 = 3d
60 = 3d
d = 60/3 = 20
Therefore, d = 20. This implies that, there is a difference of 20 between successive numbers.
The number sequence is as follow:
-1, 19, 39, 59.
