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2 years ago

In ABC, AB=5, BC=9, and AC=8. choose the angle measures in order from greatest to least.

Mathematics

2 answers:

shepuryov [24]2 years ago

6 0

angle measures in order from greatest to least.
<BAC, <ABC, <ACB

hope it help.

ra1l [238]2 years ago

3 0

A, B then C. The side across from a is the largest, then the side aceoss from b us second. Then c is last

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Suppose that – in any given time period – a certain stock is equally likely to go up 1 unit or down 1 unit, and that the outcome

Scorpion4ik [409]

Answer:

Step-by-step explanation:

From the given information:

Let X represent the amount of the stock that goes up in the first period; &

Let Y denote the cumulative amount that goes up in the first three periods.

Then,

$X= X_1 + X_2 \\ \\ \\EX= EX_1 +EX_2\\ \\\\Now ; EX = 0 \\ \\ EX = \dfrac{1}{2}\times 1 + \dfrac{1}{2}\times -1 \\ \\ EX = \dfrac{1}{2}-\dfrac{1}{2} \\ \\ EX = 0$

$Cov(x,y) = Var(X_1) +Var(X_2) \\ \\ =\dfrac{1}{2}(1+1) + \dfrac{1}{2}(1+1) \\ \\ = \dfrac{1}{2}(2)+ \dfrac{1}{2}(2) \\ \\ = 1+1 \\ \\ =2$

$Var (X) = Var (X_1+X_2)\\ \\ = 2 \ Var(X_1) \\ \\ = 2 \times (1) \\ \\ = 2$

$Var (Y) = Var (X_1 +X_2+X_3) \\ \\ = 3 \times Var(X_1) = \\ \\ = 3 \times 1\\ \\ = 3$

∴

$Corr(x,y) = \dfrac{2}{\sqrt{6}} \\ \\ = \dfrac{2}{\sqrt{2\times 3}} \\ \\= \sqrt{\dfrac{2}{3}}$

3 0

1 year ago

You are debating about whether to buy a new computer for $800.00 or a refurbished computer with the same equipment for $640.00.

Xelga [282]

The difference
800−640
=160

160×(1+0.045)
=167.2

3 0

2 years ago

Read 2 more answers

Kameron has 9 video games at his house. This is half as many games as Kevin has. Write an equation that demonstrates the relatio

Illusion [34]

Answer:

The answer is 18

Step-by-step explanation: Because 9 + 9 = 18 so therefore Kameron and Kevin has 27 video game in total :/

6 0

2 years ago

Freshmen and Sophomores Solve by setting up a system of linear equations with 2 variables and 2 unknowns. A total of 1,595 first

VMariaS [17]

Let S = the sophomores
Let R = the freshmen
Short Answer C
s + r = 1595 (1)
s + 15 = r (2)

Substitute for r from equation (2) into equation (1)
s + s + 15 = 1595 Combine like terms
2s + 15 = 1595 Subtract 15 from both sides
2s = 1595 - 15
2s = 1580 Divide by 2
s = 1580/2
s = 795 sophmores.

s + r = 1595
795 + r = 1595 Subtract 795 from both sides
r = 1594 - 795
r = 800 Freshmen

Answer C <<<<<<

8 0

2 years ago

Read 2 more answers

An experiment was performed to compare the abrasive wear of two different laminated materials. Twelve pieces of material 1 were

vladimir1956 [14]

Answer:

The calculated value Z= 4.8389> 1.96 at 0.05 level of significance.

The null hypothesis is rejected.

There is significance difference between that the abrasive wear of material 1 not exceeds that of material 2 by more than 2 units

Step-by-step explanation:

Step:-(1)

Given data the samples of material 1 gave an average (coded) wear of 85 units with a sample standard deviation of 4

Mean of the first sample x₁⁻ =85

standard deviation of the first sample S₁ = 4

Given data the samples of material 2 gave an average of 81 and a sample standard deviation of 5.

Mean of the first sample x₂⁻ =81

standard deviation of the first sample S₂ = 5

Step :-2

Null hypothesis: H₀: there is no significance difference between that the abrasive wear of material 1 exceeds that of material 2 by more than 2 units

Alternative hypothesis :H₁: there is significance difference between that the abrasive wear of material 1 exceeds that of material 2 by more than 2 units

Assume the populations to be approximately normal with equal variances.σ₁² =σ₂²

The test statistic

$Z= \frac{x_{1} -x_{2} }{\sqrt{\frac{S^2_{1} }{n_{1} } +\frac{S^2_{2} }{n_{2} } } }$

Given n₁=n₂=60.

$Z= \frac{85-81 }{\sqrt{\frac{(4)^2 }{60 } +\frac{5^2 }{60} } }$

On calculation, we get

Z = $\frac{4}{\sqrt{0.6833} }$

z = 4.8389

The tabulated value Z =1.96 at 0.05 level of significance.

The calculated value Z= 4.8389> 1.96 at 0.05 level of significance.

The null hypothesis is rejected.

Conclusion:-

there is significance difference between that the abrasive wear of material 1 not exceeds that of material 2 by more than 2 units.

3 0

2 years ago