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Semenov [28]
1 year ago
15

Suppose that – in any given time period – a certain stock is equally likely to go up 1 unit or down 1 unit, and that the outcome

s of different periods are independent. Let X be the amount the stock goes up (either 1 or −1) in the first period, and let Y be the cumulative amount it goes up in the first three periods. Find the correlation between X and Y.
Mathematics
1 answer:
Scorpion4ik [409]1 year ago
3 0

Answer:

Step-by-step explanation:

From the given information:

Let X represent the amount of the stock that goes up in the first period; &

Let Y denote the cumulative amount that goes up in the first three periods.

Then,

X= X_1 + X_2 \\ \\ \\EX=  EX_1 +EX_2\\ \\\\Now ; EX = 0 \\ \\ EX = \dfrac{1}{2}\times 1 + \dfrac{1}{2}\times -1 \\ \\ EX = \dfrac{1}{2}-\dfrac{1}{2} \\ \\ EX = 0

Cov(x,y) = Var(X_1) +Var(X_2) \\ \\ =\dfrac{1}{2}(1+1) + \dfrac{1}{2}(1+1) \\ \\ = \dfrac{1}{2}(2)+ \dfrac{1}{2}(2)  \\ \\ = 1+1  \\ \\ =2

Var (X) = Var (X_1+X_2)\\ \\ = 2 \ Var(X_1)  \\ \\ = 2 \times (1) \\ \\  = 2

Var (Y) = Var (X_1 +X_2+X_3) \\ \\ = 3 \times Var(X_1) = \\ \\ = 3 \times 1\\   \\ = 3

∴

Corr(x,y) = \dfrac{2}{\sqrt{6}} \\ \\ = \dfrac{2}{\sqrt{2\times 3}} \\ \\= \sqrt{\dfrac{2}{3}}

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2 years ago
An anthropologist finds that a prehistoric bone contains less than 8.1% of the amount of Carbon-14 the bones would have containe
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Answer:

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Step-by-step explanation:

The formula you use for this type of decay problem is the one that uses the decay constant as opposed to the half life in years.  We are given the k value of .00012.  If we don't know how much carbon was in the bones when the person was alive, it would be safer to say that when he was alive he had 100% of his carbon.  What's left then is 8.1%.  Because the 8.1% is left over from 100% after t years, we don't need to worry about converting that percent into a decimal.  We can use the 8.1.  Here's the formula:

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8.1=100e^{-.00012t}

Begin by dividing the 100 on both sides to get

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Now take the natural log of both sides.  Since the base of a natual log is e, natural logs and e "undo" each other, much like taking the square root of a squared number.

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4 0
2 years ago
A dealer paid $10,000 for a boat at an auction. At the dealership, a salesperson sold the boat for 30% more than the auction pri
pickupchik [31]
<span>Given situation:
=> A deadler paid $10 000 for a boat at an auction.
=> At the dealership, a sales person sold the boat for 30% more than the auction price
=> 10 000 dollars + 30%
=> Then the salesperson received a commission of 25% of the difference between the auction price and the dealership price
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=> 10 000 x .30 = 3000
=> 10 000 + 3 000 = 13 000, he sell it for this price
=> then he received a commission
=> 13 000 – 3 000 = 10 000
=> 10 000 x .25
=> 2500 , his commission </span>



7 0
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