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Ugo [173]
2 years ago
12

Smith High School offers a baseball camp that is $75 for 4 days of camp and a basketball camp that is $100 for 5 days of camp. W

hich camp is a better deal and by how much?
A) baseball camp by $1.25 a day
B) basketball camp by $1.25 a day
C) baseball camp by $2.50 a day
D) basketball camp by $2.50 a day
Mathematics
2 answers:
nirvana33 [79]2 years ago
7 0

Answer:

Option A. is the answer.

Step-by-step explanation:

Smith high school offers a baseball camp that is $75 for 4 days of camp and  basketball camp with the charges $100 for 5 days.

It is for the sure that a camp which offers less charges for a day will be the better deal.

Per day cost of baseball camp = \frac{75}{4}=18.75

Per day cost of basketball camp = \frac{100}{5}=20

Now we have to find the difference of per day cost of the camps.

per day cost of basketball camp - per day cost of baseball camp

= 20 - 18.75

= $1.25

So baseball camp is a better deal by $1.25 a day.

castortr0y [4]2 years ago
5 0
A) baseball camp by $1.25 a day

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A. The area of the rectangle is 88 square inches.

C. The equation x² – 3x – 88 = 0 can be used to solve for the length of the rectangle.

Step-by-step explanation:

The question is incomplete. Here is the complete question.

A rectangular piece of paper has a width that is 3 inches less than its length. It is cut in half along a diagonal to create two congruent right triangles with areas of 44 square inches. Which statements are true? Check all that apply.

A.The area of the rectangle is 88 square inches.

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C.The equation x2 – 3x – 88 = 0 can be used to solve for the length of the rectangle.

D.The triangle has a base of 11 inches and a height of 8 inches.

The rectangle has a width of 4 inches.

If a rectangular piece of paper has a width that is 3 inches less than it's length and it is cut in half along a diagonal to create two congruent right triangles with areas of 44 square inches, the width of the rectangle will be equal to the base of the each of the triangle, and the length equal to the height of the triangle.

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Area of the triangle = 1/2 * base * height

Area of the triangle = 1/2 (L-3)L

If the area of the congruent triangles is 44in², then;

44 = 1/2 (L-3)L

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88 = L²-3L

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