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SpyIntel [72]
1 year ago
7

A boat is traveling east across a river that is 112 meters wide at 8 meters per second. If the river has a northward current of

5 meters per second, what is the resultant speed of the motorboat rounded to the nearest tenth? A.3.0 m/s B.9.4 m/s C. 13.0 m/s D. 8.6 m/s
Mathematics
2 answers:
andreyandreev [35.5K]1 year ago
6 0
This is the concept of application of the Pythagorean theorem. The resultant speed of the motorboat which is crossing the river that has a northward current of 5 m/s at a speed of 8 m/s will be given by:
c^2=a^2+b^2
c^2=8^2+5^2
c^2=64+25
c^2=89
c=sqrt89
c=9.4 m/s
Mrac [35]1 year ago
5 0

Answer:

The answer would be 9.4m/s I can't provide the explanation sorry.

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Bob Rohrman is offering a 2016 Toyota Camry for $29,000. If you have a $5,000 down payment and are able to borrow the rest at a
vova2212 [387]

Answer:

The monthly payment will be $531.12

Step-by-step explanation:

Consider the provided information.

After paying $5,000 down payment you need to pay:

$29,000-$5,000=$24,000

APR is 2.99% or APR = 0.299%

Therefore, r=\frac{0.0299}{12}

n = 48

We can calculate the monthly payment by using the formula:

P=\frac{r(PV)}{1-(1+r)^{-n}}

Where P is the monthly payment, PV is the present value, r is the rate per period and n is the number of period.

Substitute the respective values in the above formula we get,

P=\frac{\frac{0.0299}{12}(24000)}{1-(1+\frac{0.0299}{12})^{-48}}

P=\frac{59.8}{0.112593}

P\approx531.12

Hence, the monthly payment will be $531.12

4 0
1 year ago
You have two circles, one with radius r and the other with radius R. You wish for the difference in the areas of these two circl
gtnhenbr [62]

Answer:

maximum difference of radii =(r-R)=\frac{1}{2\pi ^{2}}

Step-by-step explanation:

We know that area of circle is given by

A=\pi \times (radius)^{2}

For circle with radius 'r' we have

A_{1}=\pi \times (r)^{2}

For circle with radius 'R' we have

A_{2}=\pi \times (R)^{2}

Now according to given condition we have

A_{1}-A_{2}\leq \frac{5}{\pi }

\Rightarrow \pi r^{2}-\pi R^{2}\leq \frac{5}{\pi }\\\\\Rightarrow (r^{2}-R^{2})\leq \frac{5}{\pi ^{2}}\\\\(r+R)(r-R)\leq \frac{5}{\pi ^{2}}\\\\\because (a^{2}-b^{2})=(a+b)(a-b)\\\\(r+R)=10(Given)\\\\\Rightarrow(r-R)\leq \frac{5}{10\pi ^{2}}\\\\\therefore (r-R)\leq\frac{1}{2\pi ^{2}}

Thus maximum difference of radii =(r-R)=\frac{1}{2\pi ^{2}}

6 0
2 years ago
Many us employess received a 3% raise in 2012 suppose an employee made 47,000 in 2011 and received a 3% raise. What did she make
WITCHER [35]
First lets get 3% into decimal form. 

3% is 3/100  = 0.03

Now multiply 0.03 by 47000 to get how much extra money she was going to get. 

47000 * 0.03 = 1410

Now we just add
47000 + 1410 = 48410 is what she was going to make in 2012

Another way to do this is 

(47000)(1+0.03) = 48410

you would use (1+0.03) which tells you she increased in pay. 
4 0
1 year ago
The energy transfer diagram represents the energy of a person diving into a pool. A wide arrow labeled gravitational potential e
Citrus2011 [14]

Answer:

The amount of thermal energy that is generated is 1000 joules.

Step-by-step explanation:

Let consider the person diving into a pool as a closed system, that is, a system with only energy interaction with the surroundings. According to the First Law of Thermodynamics, which is a generalization of the Principle of Energy Conservation, the total energy of the system is neither destroyed, nor created, only transformed. The initial gravitational potential energy is transformed into translational kinetic and thermal energy. That is to say:

U_{g} - K - Q = 0

Where:

U_{g} - Gravitational potential energy, measured in joules.

K_{tr} - Translational kinetic energy, measured in joules.

Q - Thermal energy, measured in joules.

The thermal energy is now cleared:

Q = U_{g}-K

Given that U_{g} = 8000\,J and K = 7000\,J, the amount of thermal energy that is generated is:

Q = 8000\,J - 7000\,J

Q = 1000\,J

The amount of thermal energy that is generated is 1000 joules.

3 0
1 year ago
Read 2 more answers
The following diagram shows the path of a planet around the Sun. Kepler discovered that _____.
Phantasy [73]

The right answer is:

<em>area B = area C</em>

We can solve this problem by using Kepler's laws of planetary motion. There are three Kepler's laws. In this exercise, we need to use the second law. According to this law,<em> a line segment joining a planet and the sun sweeps out equals areas during equals intervals of time. </em>So, a certain planet sweeps out an <em>area B </em>from the point <em>P3 </em>to <em>P4</em> in an interval of time <em>t. </em>On the other hand, for the same interval of time <em>t, </em>the planet sweeps out an <em>area C </em>from point <em>P4</em> to <em>P5, </em>that is equal to the previous area according to second kepler's law.

7 0
2 years ago
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