The x-coordinate remains the same as the x-coordinate of point B.
The y-coordinate becomes the additive inverse of the y-coordinate of point B.
Answer: B. (3, -8)
Answer:
Step-by-step explanation:
Given that we assume no direct factory overhead costs (i.e., inventory carry costs) and $3 million dollars in combined promotion and sales budget, the Deal product manager wishes to achieve a product contribution margin of 35%.
Sales - variable cost = Fixed cost + profit
Here fixed cost = 3 million dollars
Sales - variable = contribution = 35%
35% should atleast meet the fixed cost
i.e. 35% = 3 million
100% = 8.57 million can be cost
Since fixed cost will not change and remain 3 million these 5,57 million can be given to material and labor costs
So material and labor cost should be limited upto 5.57 million increase.
Lets find all the numbers..
x (1st number)
x + 2 ( 2nd number)
x + 4 (3rd number)
x + 6 (4th number)
x + 8 (5th number)
x + 10 (6th number)
Now add all those expressions and set them equal to 270 because that is the total.
x + x + 2 + x + 4 + x + 6 + x + 8 + x + 10 = 270
6x + 30 = 270
6x = 240
x = 40
Now we will substitute 40 for x in the expression of the second number.
x + 2
40 + 2
42
So the second number is 42
Hope this helps :)
Answer:
99.85%
Step-by-step explanation:
The lifespans of meerkats in a particular zoo are normally distributed. The average meerkat lives 10.4 years; the standard deviation is 1.9 years.
Use the empirical rule (68-95-99.7%) to estimate the probability of a meerkat living less than 16.1 years.
Solution:
The empirical rule states that for a normal distribution most of the data fall within three standard deviations (σ) of the mean (µ). That is 68% of the data falls within the first standard deviation (µ ± σ), 95% falls within the first two standard deviations (µ ± 2σ), and 99.7% falls within the first three standard deviations (µ ± 3σ).
Therefore:
68% falls within (10.4 ± 1.9). 68% falls within 8.5 years to 12.3 years
95% falls within (10.4 ± 2*1.9). 95% falls within 6.6 years to 14.2 years
99.7% falls within (10.4 ± 3*1.9). 68% falls within 4.7 years to 16.1 years
Probability of a meerkat living less than 16.1 years = 100% - (100% - 99.7%)/2 = 100% - 0.15% = 99.85%
