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Grace [21]
2 years ago
11

Susan charges $8 per hour walking her neighbor’s dog. She charges $12 per hour babysitting. Part A: Define the variables. Part B

: Write an expression to represent the amount Susan earns dog walking and babysitting
Mathematics
1 answer:
Anna35 [415]2 years ago
7 0

Answer:

the total she earns with "d" hours of dog walking and "b" hours of babysitting is given by:  8 d + 12 b

Step-by-step explanation:

If we use "d" to represent the number of hours that Susan walks the dog, and we define "b" as the number of hours she babysits, then the expression that represents the amount she earns by walking the dog is: $8 times d = 8 d

Similarly, the amount she earns by babysitting is $12 times b = 12 b

Then the total she earns with "d" hours of dog walking and "b" hours of babysitting is:  8 d + 12 b

You might be interested in
A normal distribution curve, where x = 70 and σ = 15, was created by a teacher using her students’ grades. What information abou
mash [69]

Answer:

The median and mode of the students grade is 70.

Most of the students scored between 40 and 100.

Step-by-step explanation:

From the provided information it can be seen that the mean of the distribution is, <em>μ</em> = 70 and the standard deviation is, <em>σ</em> = 15.

For a Normal distributed data the mean, median and mode are the same.

So, the median and mode of the students grade is 70.

The standard deviation of the data represents the spread of the observation, i.e. how dispersed the values are along the curve.

In statistics, the 68–95–99.7 rule, also recognized as the empirical rule, is a shortcut used to recall that 68.27%, 95.45% and 99.73% of the values of a Normally distributed data lie within one, two and three standard deviations of the mean, respectively.

P(\mu-\sigma  

P(\mu-2\sigma

P(\mu-3\sigma

Assuming that maximum marks of the exam is 100, it can be said that most of the students scored between 40 and 100.

3 0
2 years ago
Read 2 more answers
HELP ASASP PLEASE!!!!!!! What is the following simplified product? Assume x&gt;/0
luda_lava [24]
Answer: Third option.
Please, see the detailed solution in the attache file.
Thanks

6 0
2 years ago
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Five days a week, you carpool with 3 co-workers and take turns driving each week. It is 14 miles from your home to your office.
Vladimir [108]

you will save 10 gallons

7 0
2 years ago
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During the 2015-16 NBA season, J.J. Redick of the Los Angeles Clippers had a free throw shooting percentage of 0.901 . Assume th
ser-zykov [4K]

Answer: 0.5898

Step-by-step explanation:

Given :  J.J. Redick of the Los Angeles Clippers had a free throw shooting percentage of 0.901 .

We assume that,

The probability that .J. Redick makes any given free throw =0.901  (1)

Free throws are independent.

So it is a binomial distribution .

Using binomial probability formula, the probability of getting success in x trials :

P(X=x)^nC_xp^x(1-p)^{n-x}

, where n= total trials

p= probability of getting in each trial.

Let x be binomial variable that represents the number of a=makes.

n= 14

p= 0.901     (from (1))

The probability that he makes at least 13 of them will be :-

P(x\geq13)=P(x=13)+P(x=14)

=^{14}C_{13}(0.901)^{13}(1-0.901)^1+^{14}C_{14}(0.901)^{14}(1-0.901)^0\\\\=(14)(0.901)^{13}(0.099)+(1)(0.901)^{14}\ \ [\because\ ^nC_n=1\ \&\ ^nC_{n-1}=n ]\\\\\approx0.3574+0.2324=0.5898

∴ The required probability = 0.5898

5 0
2 years ago
PLEASE HELP ME!
algol13

Step-by-step explanation:

1.\sum_{i=1}^{5}3i

The simplest method is "brute force".  Calculate each term and add them up.

∑ = 3(1) + 3(2) + 3(3) + 3(4) + 3(5)

∑ = 3 + 6 + 9 + 12 + 15

∑ = 45

2.\sum_{k=1}^{4}(2k)^{2}

∑ = (2×1)² + (2×2)² + (2×3)² + (2×4)²

∑ = 4 + 16 + 36 + 64

∑ = 120

3.\sum_{k=3}^{6}(2k-10)

∑ = (2×3−10) + (2×4−10) + (2×5−10) + (2×6−10)

∑ = -4 + -2 + 0 + 2

∑ = -4

4. 1 + 1/4 + 1/16 + 1/64 + 1/256

This is a geometric sequence where the first term is 1 and the common ratio is 1/4.  The nth term is:

a = 1 (1/4)ⁿ⁻¹

So the series is:

\sum_{j=1}^{7}(\frac{1}{4})^{j-1}

5. -5 + -1 + 3 + 7 + 11

This is an arithmetic sequence where the first term is -5 and the common difference is 4.  The nth term is:

a = -5 + 4(n−1)

a = -5 + 4n − 4

a = 4n − 9

So the series is:

\sum_{j=1}^{5}(4j-9)

5 0
2 years ago
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