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nekit [7.7K]
2 years ago
10

James is 612 centimeters tall how many decimeters is this

Mathematics
2 answers:
melamori03 [73]2 years ago
8 0
This equals to 6.12 decimeters
beks73 [17]2 years ago
4 0
James is 61.2 decimeters
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Hope this helps but I think it might be:
Part A: c=0.75p
the cost of shipping for 2 pounds
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c=0.75*2
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A number is written with the following factorization 2x2x2x4x5. Is this factorization is prime factorization? Explain why or why
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The number 2*2*2*4*5 is not in its prime factorization because not all the factors are prime numbers. A prime number is a number that has no other factors except for 1 and itself.
4 is not a prime number, since it can be divided by 2. The number can be broken down into its prime factors by dividing by 2, and it becomes 2*2.

Therefore, the factorization of the number 2*2*2*4*5 can be broken down to 2*2*2*2*2*5.
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Hank bought 5 meters of ribbon for $4. The ribbon costs -$0.008, 0.08, $0.8- per -millimeter, centimeter, kilometer-. Choose one
aleksandrvk [35]
To determine the cost of each meter of the ribbon, we divide the cost for 5 meters of ribbon by 5. That is,
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Rena is building a 1:1801:1801, colon, 180 scale model of a real castle. Her model has a rectangular base that is 333 feet wide
liubo4ka [24]

Answer:

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Step-by-step explanation:

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A cell phone company is looking to place a new tower to service 3 cities. In order for it to best service each city, it needs to
omeli [17]

Answer:

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Step-by-step explanation:

The circumscribed circle or <em>circumcircle</em> of a polygon is a circle that passes through all the vertices of the polygon. The center of the circle, the circumcenter, is equidistant from all of the polygon's vertices.

The center is found at the point of intersection between the perpendicular bisectors of any two (non-parallel) chords of the circle. That is, <em>the perpendicular bisectors of any two of the sides of the triangle joining the cities will intersect at the circumcenter</em>.

The method of locating the center of the circle this way is simple and effective.

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