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nekit [7.7K]
2 years ago
10

James is 612 centimeters tall how many decimeters is this

Mathematics
2 answers:
melamori03 [73]2 years ago
8 0
This equals to 6.12 decimeters
beks73 [17]2 years ago
4 0
James is 61.2 decimeters
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The graphs below have the same shape. What is the equation for the red graph?
Serhud [2]
Your answer would be B because even though it's the same shape the red shape is 2 times bigger.......your exponent 4 stays 4
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2 years ago
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Five hundred sixth-grade students
viktelen [127]
<h3>The ratio in three ways are 500 : 125 or 100 : 25 or 4 : 1</h3>

<em><u>Solution:</u></em>

Given that,

Five hundred sixth-grade students  were surveyed

Which means,

sixth-grade students = 500

125 had traveled on an airplane

<em><u>What is the ratio of total sixth-grade students to the number of students who had  traveled on an airplane?</u></em>

Therefore,

total sixth-grade students : students  traveled on airplane = 500 : 125

<h3>Ratio = 500 : 125</h3>

Reduce to lowest terms,

Divide both sides by 5

<h3>Ratio = 100 : 25</h3>

Further reduce to simplest terms,

Divide both sides by 25

<h3>Ratio = 4 : 1</h3>

Thus the ratio in three ways are 500 : 125 or 100 : 25 or 4 : 1

6 0
2 years ago
Identify the range of the function shown in the graph
e-lub [12.9K]

Step-by-step explanation:

answer is c

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7 0
2 years ago
The student council raised $2,790 during its annual fundraiser. The money was shared equally among the Events Committee, the Spo
irina [24]

Answer:

77

Step-by-step explanation:

$2790 is shares equally between 3 committees. each committee would get - $2790 / 3 = $930

If a shirt costs $12 and the Sports Committee gets $930, the committee would get $930 / $12 = 77.5

The committee cannot get half a shirt, so the greatest number of shirt that can be purchased is 77

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2 years ago
The mean annual salary for intermediate level executives is about $74000 per year with a standard deviation of $2500. A random s
lidiya [134]

Answer:

11.51% probability that the mean annual salary of the sample is between $71000 and $73500

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 74000, \sigma = 2500, n = 36, s = \frac{2500}{\sqrt{36}} = 416.67

What is the probability that the mean annual salary of the sample is between $71000 and $73500?

This is the pvalue of Z when X = 73500 subtracted by the pvalue of Z when X = 71000. So

X = 73500

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{73500 - 74000}{416.67}

Z = -1.2

Z = -1.2 has a pvalue of 0.1151

X = 71000

Z = \frac{X - \mu}{s}

Z = \frac{71000 - 74000}{416.67}

Z = -7.2

Z = -7.2 has a pvalue of 0.

0.1151 - 0 = 0.1151

11.51% probability that the mean annual salary of the sample is between $71000 and $73500

8 0
2 years ago
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