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lord [1]
2 years ago
11

The pizza has an area of 78.5 in². What is the minimum width of a placemat that can be placed underneath it so that the pizza do

es not touch the table? Use 3.14 for pi. someone pls help me
Mathematics
2 answers:
xz_007 [3.2K]2 years ago
4 0

Answer:

The minimum width of the placemat is 10 inches.

Step-by-step explanation:

Let suppose that placemat has a square form, whose width must be at least equal to the diameter of the pizza, so that pizza does not touch the table. Hence, the following relationship is obtained:

w = D

Where:

w - Width of the placemat, measured in inches.

D - Diameter of pizza, measured in inches.

The area of the pizza, measured in square inches, is determined by this formula:

A = \frac{\pi}{4} \cdot D^{2}

The diameter is cleared afterwards:

D = \sqrt{\frac{4\cdot A}{\pi} }

If A = 78.5\,in^{2} and \pi = 3.14, then:

D = \sqrt{\frac{4\cdot (78.5\,in^{2})}{3.14} }

D = 10\,in

The minimum width of the placemat is 10 inches.

erma4kov [3.2K]2 years ago
3 0

Answer:

10 inches

Step-by-step explanation:

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