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2 years ago

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The pizza has an area of 78.5 in². What is the minimum width of a placemat that can be placed underneath it so that the pizza do

es not touch the table? Use 3.14 for pi. someone pls help me

2 answers:

xz_007 [3.2K]2 years ago

4 0

Answer:

The minimum width of the placemat is 10 inches.

Step-by-step explanation:

Let suppose that placemat has a square form, whose width must be at least equal to the diameter of the pizza, so that pizza does not touch the table. Hence, the following relationship is obtained:

$w = D$

Where:

$w$ - Width of the placemat, measured in inches.

$D$ - Diameter of pizza, measured in inches.

The area of the pizza, measured in square inches, is determined by this formula:

$A = \frac{\pi}{4} \cdot D^{2}$

The diameter is cleared afterwards:

$D = \sqrt{\frac{4\cdot A}{\pi} }$

If $A = 78.5\,in^{2}$ and $\pi = 3.14$ , then:

$D = \sqrt{\frac{4\cdot (78.5\,in^{2})}{3.14} }$

$D = 10\,in$

The minimum width of the placemat is 10 inches.

erma4kov [3.2K]2 years ago

3 0

Answer:

10 inches

Step-by-step explanation:

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Answer:

-1.13 m/s

Step-by-step explanation:

Parameters given:

Mass of first footballer, M = 92 kg

Initial velocity of first footballer, U = 6.5 m/s (taking North to be the +ve y axis)

Mass of second footballer, m = 85 kg

Initial velocity of second footballer, u = -6.0 m/s (taking South to be the -ve y axis)

Final velocity of first footballer, V = 2.0 m/s

We need to find the final velocity of the second football (v)

Applying the principle of conservation of momentum, we have that, in a system:

Total Initial Momentum = Total Final Momentum

(M * U) + (m * u) = (M * V) + (m * v)

(92 * 6.5) + (85 * -6) = (92 * 2) + (85 * v)

598 - 510 = 184 + 85v

88 = 184 + 85v

88 - 184 = 85v

-96 = 85v

=> v = -96 / 85

v = -1.13 m/s

The final velocity of the 85 kg player is -1.13 m/s i.e 1.13 m/s South

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A flag stick on a golf course that is 6 1/2 feet tall casts a 9 3/4 foot shadow while a golfer nearby casts a 8 3/4 foot shadow.

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2 years ago

Yesterday's World Cup final had viewing figures of 138,695,157.<br><br> What is the value of the 3?

crimeas [40]

Answer:

The value of the 3 is 30,000,000.

Step-by-step explanation:

From the digit at the right, you go multiplying each element by 10 powered to a counter that starts at zero and increases at every digit. So:

Our counter is i

i = 0;

v(7) is the value of the 7

$v(7) = 7*10^{0} = 7$

i = 1;

v(5) is the value of the 5

$v(5) = 5*10^{1} = 50$

i = 2;

v(1) is the value of the 1

$v(1) = 1*10^{2} = 100$

i = 3;

v(5) is the value of the 5

$v(5) = 5*10^{3} = 5,000$

i = 4;

v(9) is the value of the 9

$v(9) = 9*10^{4} = 90,000$

i = 5;

v(6) is the value of the 6

$v(6) = 6*10^{5} = 600,000$

i = 6;

v(8) is the value of the 8

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2 years ago

Which ordered pair minimizes the objective function C = 60x + 85y?. (0, 160). (55, 70). (80, 50). (170, 0)

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Step-by-step explanation:

The given objective function is $C = 60x + 85y$

To check that which ordered pair is minimizing the objective function-we will substitute all the ordered pair one by one in the given function and we will calculate the value of C. The ordered pair which will give the minimum value will be the answer.

For (0, 160)

$C=60\times 0+85\times 160=13600$

For (55, 70)

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For (80, 50)

$C=60\times 80+85\times 50=9050$

For (80, 50)

$C=60\times 170+85\times 0=10200$

Hence the ordered pair which minimizes the objective function is (80, 50)

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2 years ago

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