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2 years ago

Which ordered pair minimizes the objective function C = 60x + 85y?. (0, 160). (55, 70). (80, 50). (170, 0)

Mathematics

2 answers:

dangina [55]2 years ago

3 0

Step-by-step explanation:

The given objective function is $C = 60x + 85y$

To check that which ordered pair is minimizing the objective function-we will substitute all the ordered pair one by one in the given function and we will calculate the value of C. The ordered pair which will give the minimum value will be the answer.

For (0, 160)

$C=60\times 0+85\times 160=13600$

For (55, 70)

$C=60\times 55+85\times 70=9250$

For (80, 50)

$C=60\times 80+85\times 50=9050$

For (80, 50)

$C=60\times 170+85\times 0=10200$

Hence the ordered pair which minimizes the objective function is (80, 50)

Vera_Pavlovna [14]2 years ago

3 0

The ordered pair which minimizes the function C = 60x + 85y is ordered pair (80, 50). The correct answer between all the choices given is the third choice.

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Step-by-step explanation:

Given

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First, calculate the value of q

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So, we have:

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Solving (a): Fails to close on the 4th attempt

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So, we have:

$Pr = p*p*p*q$

$Pr = p^3*q$

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$Pr = 0.0864$

Solving (b): He closes for the first time on the 3rd attempt

This means that he fails to close the first two attempts. The event is represented as: q q p

So, we have:

$Pr = q * q * p$

$Pr = q^2 * p$

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$Pr = 0.096$

Solving (c): First he closes is his 2nd attempt

This means that he fails to close the first. The event is represented as: q p

So, we have:

$Pr = q * p$

$Pr = 0.40 * 0.60$

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Solving (d): The first he close is one of his 3 attempts

To do this, we make use of complement rule

The event that he does not close any of his first three attempts is: q q q

The probability is:

$Pr = q*q*q$

$Pr = q^3$

The opposite is that the first he closes is one of the first three

So, we have:

$Pr' = 1- Pr$ --- complement rule

$Pr' = 1- q^3$

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$Pr' = 1- 0.064$

$Pr' = 0.936$

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Rouding up

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