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adoni [48]
2 years ago
15

In ΔHIJ, the measure of ∠J=90°, JI = 48, IH = 73, and HJ = 55. What is the value of the tangent of ∠H to the nearest hundredth

Mathematics
1 answer:
babunello [35]2 years ago
3 0

Answer:

The value of the tangent of ∠H to the nearest hundredth is 41.11⁰

Step-by-step explanation:

Given;

∠J=90°

JI = 48

IH = 73

HJ = 55

If we sketch this triangle, we will observe that  ΔHIJ is a right angled triangle, with hypotenuse as "IH", opposite as "JI" and adjacent as "HJ".

To determine the value of the tangent of ∠H, we apply the following formula;

Tan \ H = \frac{Opposite \ side}{Adjacent \ side} = \frac{JI}{HJ} \\\\Tan \ H =\frac{48}{55} \\\\Tan \ H = 0.8727\\\\H = Tan^{-1} (0.8727)\\\\H = 41.111^o\\\\H = 41.11^o (nearest \ hundredth)

Therefore, the value of the tangent of ∠H to the nearest hundredth is 41.11⁰

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In Exercises 1 and 2, find the equilibrium solutions of the differential equation specified.1) dy/dt = (y + 3)/(1 - y)2) dy/dt =
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Answer:

1. Equilibrium solution: y= -3

2. Equilibrium solution y= ±1.414

Step-by-step explanation:

Thinking process:

The equilibrium solution can only be derived when \frac{dy}{dt}  = 0

1. Let's look at the first equation:

\frac{dy}{dt} = \frac{(y+3)}{(1-y)}

equating \frac{dy}{dt}  = 0 to the expression \frac{(y+3)}{(1-y)} gives

y + 3 = 0

     y = -3

Therefore, the equilibrium solution occurs at y = -3

2. Let's look at the second solution:

\frac{dy}{dy} = \frac{(t^{2}- 1) (y^{2}-2) }{y^{2}-4 }

dividing each side by (t²-1) gives

1/(t²-1)\frac{dy}{dt} = (y²-2)/ (y²-4)

factorizing the right hand side gives:

at equilibrium:  \frac{dy}{dt}  = 0, then

y² - 2 = 0

solving for y gives y = ±√2

                                 = ±1.414

5 0
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Your most appropriate choice seems to be $4178, which corresponds to 186 days' taxes.

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lilavasa [31]

Pergunta correta:

Seja 17x + 51y = 102. Qual é o valor de 9x + 27a? (A) 54 (B) 36 (C) 34 (D) 18 (E) indeterminado

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Explicação passo a passo:

17x + 51y = 102 - - - - equação 1

Divulgue até 17

x + 3y = 6 - - - - - - - Equação 2

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Comparando as equações 2 e 3

(Equação 3) = 9 × (equação 2)

Isso é, 9x + 27y = 9 × (x + 3y = 6)

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Step-by-step explanation:

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