The organizers of a fair projected a 25 percent increase in attendance this year over that of last year, but attendance this yea
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<h3>Answer: 680 different combinations</h3>
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Explanation:
If order mattered, then we'd have 17*16*15 = 4080 different permutations. Notice how I started with 17 and counted down 1 at a a time until I had 3 slots to fill. We count down by 1 because each time we pick someone, we can't pick them again.
So we have 4080 different ways to pick 3 people if order mattered. But again order doesn't matter. All that counts is the group itself rather than the individual or how they rank. There are 3*2*1 = 6 ways to order any group of three people, which means there are 4080/6 = 680 different combinations possible.
An alternative is to use the nCr formula with n = 17 and r = 3. That formula is
where the exclamation marks indicate factorials
Answer:
(a) 0.10
(b) 0.70
(c) 0.30
Step-by-step explanation:
Items b and c are missing from the question:
(b) What is the probability that at least one of the two members whose name begins with C is selected?
(c) If the five faculty members have taught for 3, 6, 7, 10, and 14 years, respectively, at the university, what is the probability that the two chosen representatives have a total of at least 18 years teaching experience there?
The number of ways to select two representatives out of 5 people is given by the combination of picking two out of 5:
(a) Since there is only one way for both Anderson and Box to be selected, the probability is:
(b) There are four ways for Cox to be selected, four ways for Cramer to be selected, and one where both are selected. The probability is:
(c) The only possible ways for the total of number of years to exceed 18 is by selecting: (14;6 14;7 14;10). Therefore the probability is: