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pogonyaev
1 year ago
14

A bank says you can double your money in 8 years if you put $2,000 In a simple interest account. what annual interest rate does

the bank pay?
Mathematics
2 answers:
Monica [59]1 year ago
5 0
A = P*r*t
A = overall value
P = principal (initial value)
r = annual interest
t = time (in years)

Plug in what we have:
4000 = 2000*r*8
Simplify:
0.25 = r
The annual interest is 25%
Viktor [21]1 year ago
3 0

Answer:

the correct answer is 12.5 percent

Step-by-step explanation:

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A County Superintendent of Highways is interested in the numbers of different types of vehicles that regularly travel within his
Karolina [17]

Answer:

a) The ratio of passenger cars to pickup trucks is \frac{5}{7}

The ratio of pickup trucks to passenger cars is \frac{7}{5}

The ratio of passenger cars to total vehicles is \frac{5}{12}

The ratio of pickup trucks to total vehicles is \frac{7}{12}

b) The tape diagram is shown in the attached picture.

c) The tape diagram has 12 equal-sized parts.

d) The total quantity that the tape diagram represent is 192.

e) The value of each individual part of the tape is 16.

f) There were registered 80 passenger cars and 112 pickup trucks.

Step-by-step explanation:

a) According to the information in the problem, that for every 5 passenger cars registered, there were 7 pickup trucks registered.

So the ratios are:

Passenger cars to pickup trucks: \frac{5}{7}

Pickup trucks to passenger cars: \frac{7}{5}

If we calculate the total vehicles: 5+7=12

So, we can get two ratios more:

Passenger cars to total vehicles is \frac{5}{12}

Pickup trucks to total vehicles is \frac{7}{12}

b) We make a tape diagram where each box represents a vehicle so we draw 5 boxes for cars and 7 boxes for pickup trucks.

c) If we count the total quantity of boxes, there are 12.

d) This diagram represents the total quantity of registrations in August which is 192.

e) To get the representation of each part of the tape diagram we have to divide 192 by 12. 192÷12=16

f) Finally, we multiply 16 by the number of boxes of each type of vehicle:

Cars: 16×5=80

Pickup trucks: 16×7=112

6 0
2 years ago
PLEASE HELP ASAP: A particle is moving with velocity v(t) = t2 – 9t + 18 with distance, s measured in meters, left or right of z
dimaraw [331]
1) \frac{v(8)-v(0)}{8 - 0} = \frac{10-18}{8} = -1\frac{m}{s}.
2) v(5) = 5^2-9*5+18 = 25-45+18 = -2\frac{m}{s}.
3) The particle is moving right when the velocity function is positive: 0\ \textless \ t\ \textless \ 3 or 6\ \textless \ t\ \textless \ 8.
4) When 0\ \textless \ t\ \textless \ \frac{9}{2} the particle is slowing down because the acceleration is close to zero \Rightarrow the particle is speeding up when acceleration is increasing away from zero: \frac{9}{2}\ \textless \ t\ \textless \ 8.
5) (\frac{1}{8})* \int\limits^8_0 {t^2-9t+18dt}=\frac{1}{8}*(\frac{t^3}{3}-(\frac{9}{2}*t^2+18t)_{0}^{8}= \\=(\frac{1}{8})*(\frac{8^3}{3}-(\frac{9}{2})*8^2+18*8)=\frac{8^2}{3}-(\frac{9}{2})*8+18=3\frac{1}{3} \frac{m}{s}.
3 0
2 years ago
Consider a single spin of the spinner.
alex41 [277]

Answer:

"landing on a shaded portion and landing on a 3"

"landing on an unshaded portion and landing on a number less than 2 "

Step-by-step explanation:

Mutually exclusive means the events will have no intersection.

Let's look at your first choice:

"landing on a shaded portion and landing on an even number"

Landing on a shaded portion would be 1 or 4.

Landing on an even number would be 2 or 4.

There is an intersection (they contain a common element), the 4.

These events are not mutually exclusive.

Let's look at your second choice:

"landing on a shaded portion and landing on a number greater than 3"

Landing on a shaded portion would be 1 or 4.

Landing on a number greater than 3 would be just 4.

There is an intersection; they both contain 4.

These events are not mutually exclusive.

Let's look at your third choice:

"landing on a shaded portion and landing on a 3"

Landing on a shaded portion would be 1 or 4.

Landing on 3 would just be 3.

There is no common elements in the lists listed.  These events have no intersection.

These events are mutually exclusive.

Let's look at your fourth choice:

"landing on an unshaded portion and landing on an odd number"

Landing on a unshaded portion would be 2 or 3.

Landing on an odd number would be 1 or 3.

There is an intersection; they both have 3 in common.

These events are not mutually exclusive.

Let's look at your fifth choice:

"landing on an unshaded portion and landing on a number less than 2 "

Landing on an unshaded portion would 2 or 3.

Landing on a number less than 2 would be 1.

There is no intersection.

These events are mutually exclusive.

6 0
2 years ago
Read 2 more answers
What is the factored form of 36x4 – 25?
gladu [14]
36x^4 - 25=(6x^2)^2-5^2=(6x^2-5)(6x^2+5)
8 0
2 years ago
Read 2 more answers
A round wading pool has a diameter of 115\text{ cm}115 cm115, start text, space, c, m, end text and is 25\text{ cm}25 cm25, star
AveGali [126]

Answer: 6

Step-by-step explanation:

8 0
1 year ago
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