Step-by-step explanation:
dA/dt = 6 − 0.02A
dA/dt = -0.02 (A − 300)
Separate the variables.
dA / (A − 300) = -0.02 dt
Integrate.
ln(A − 300) = -0.02t + C
Solve for A.
A − 300 = Ce^(-0.02t)
A = 300 + Ce^(-0.02t)
Use initial condition to find C.
50 = 300 + Ce^(-0.02 × 10)
50 = 300 + Ce^(-0.2)
-250 = Ce^(-0.2)
C = -250e^(0.2)
A = 300 − 250e^(0.2) e^(-0.02t)
A = 300 − 250e^(0.2 − 0.02t)
Part A the coefficient is 20c and 35w, the variable is c and w representing cost and week. and the constant is 23.50.
Part B He would have 503.50 because <span><span>35</span><span>(12)</span></span>+60<span>=<span><span>420x</span>+<span>60+23.50 which would be 503.50
Part C The coefficient of the cost would change because you would be adding a 5 dollar increase!!!!!! done</span></span></span>
Answer:
d. The random variable is the number of years in which the temperature increased from the previous year.
Step-by-step explanation:
The random variable is the amount of years that have higher average temperatures than its previous year.
As the sample is from 5 years, the random variable can take values from 0 (where none of the years increase their average temperature from its previous year) to 4 (where every year increases the average temperature).
Answer:
$30
Step-by-step explanation:
Given data
Origianal price= $40
discount= 50%
Tax= 10%
Let us find the amount of the discount and tax
Discount
=50/100*40
=0.5*40
=$20
Tax
=10/100*40
=0.1*40
=$4
Hence the total cost is
=40-20+10
=$30
