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Anarel [89]
2 years ago
10

Did you get your 8 hours of sleep last night?" is a common question. In a recent survey of 151 postpartum women, the folks at th

e National Sleep Foundation found that the mean sleep time was 7.8 hours, with a standard deviation of 1.4 hours. Does the evidence suggest that postpartum women do not get enough sleep? Use α = 0.05 level of significance.
Mathematics
1 answer:
Ber [7]2 years ago
8 0

Answer:

There is evidence to suggest that postpartum women do not get enough sleep

Step-by-step explanation:

Given that in a recent survey of 151 postpartum women, the folks at the National Sleep Foundation found that the mean sleep time was 7.8 hours, with a standard deviation of 1.4 hours.

H_0: \bar x =8\\H_a: \bar x

(left tailed test at 5% significance)

Mean difference = -0.20

Std error of sample = \frac{s}{\sqrt{n} } \\=\frac{1.4}{\sqrt{151} } \\=0.114

Test statistic t = mean difference/std error =

= -1.76

df = 150

p value one tailed = 0.0402

Since p < alpha, we reject H0

There is evidence to suggest that postpartum women do not get enough sleep

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Mathew rolls a number cube labeled with the numbers 1−6. He then flips a fair coin. What is the probability that he rolls a 4 an
kap26 [50]

Answer: 0.083


Step-by-step explanation:

Numbers on cube=6

faces on coin=2

Therefore, the total outcomes=6\times2=12

Now, the favorable outcome that he rolls a 4 and flips a head=1

The probability that he rolls a 4 and flips a head=\frac{\text{favorable outcome}}{\text{total outcome}}

⇒The probability that he rolls a 4 and flips a head=\frac{1}{12}=0.083333\approx0.83.

Therefore, The probability that he rolls a 4 and flips a head=0.083

3 0
2 years ago
Read 2 more answers
Solve z3+3z2−25z−75=0 .
Basile [38]
<span>z^3 + 3z^2 -25z - 75 = 0</span>
Factor out common terms in the first two terms, then in the last two terms
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<span><span><span>(z+3)(<span>z^2</span>−25)=0
</span></span></span>Ask: When will <span>(z+3)(<span>z^2</span>−25)</span> equal zero?
When <span>z+3=0 </span>or <span><span>z^2</span>−25=0
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3 0
2 years ago
Which is a zero of the quadratic function f(x) = 16x2 32x − 9?
tankabanditka [31]
A zero of a function is the value of x for which f(x) = 0
f(x) = 16x^2 + 32x - 9 = 0
16x^2 - 4x + 36x - 9 = 0
(16x^2 - 4x) + (36x - 9) = 0
4x(4x - 1) + 9(4x - 1) = 0
(4x + 9)(4x - 1) = 0
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4x = -9 and 4x = 1
x = -9/4 and x = 1/4
8 0
1 year ago
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A man divided $9,000 among his wife, son, and daughter. The wife received twice as much as the daughter, and the son received $1
oksian1 [2.3K]
Your answer is A. x/2+1000

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5 0
2 years ago
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How much heat is produced when 100 mL of 0.250 M HCl (density, 1.00 g/mL) and 200 mL of 0.150 M NaOH (density, 1.00 g/mL) are mi
alexira [117]

Answer:

1.45 kilo joules of heat is produced when 100 mL of 0.250 M HCl and 200 mL of 0.150 M NaOH.

1.15°C is the temperature increase.

Step-by-step explanation:

HCl+NaOH\rightarrow NaCl+H_2O ,ΔH°=-58 kJ/mol

Molarity=\frac{Moles}{Volume (L)}

Molarity of HCl = 0.250 M

Volume of HCl = 100 ml = 0.1 L

Moles of HCl = n

n=0.250\times 0.1 L=0.0250 mol

Molarity of NaOH= 0.150 M

Volume of NaOH= 200 ml = 0.2 L

Moles of NaOH= n'

n'=0.150\times 0.2 L=0.030 mol

According to reaction, 1 mol of HCl reacts with 1 mol of NaOH. Then 0.0250 mole of HCl will reacts with 0.0250 mol of NaOH.

\frac{1}{1}\times 0.0250 mol=0.0250 mol of NaOH

As we can see that moles of NaOH are in excess.Hence, excessive agent.

The enthalpy of the reaction = ΔH°=-58 kJ/mol

Energy released when 0.0250 moles of HCl reacted with 0.0250 moles of NaOH:

Q=\Delta H^o\times 0.0250 mol=-58 kJ/mol\times 0.0250 mol=-1.45 kJ

(Negative sign indicates that heat is liberated.)

Mass of the HCL solution = m

Volume of HCl ,v= 100 ml

Density of HCl solution = d = 1.00 g/mL

m=d\times v=1.00 g/mL\times 100 mL=100 g

Mass of NaOH solution = m'

Volume of NaOH ,v' = 200 ml

Density of NaOH solution = d' = 1.00 g/mL

m'=d'\times v'=1.00 g/mL\times 200 mL=200 g

Mass of the solution after mixing,M = m + m' = 100  g + 200 g = 300 g

Heat absorbed by the final solution formed after mixing = Q'

Heat absorbed by the final solution formed after mixing = Heat released during reaction

Q' = -Q = -(-1.45 kJ)= 1.45 kJ=1450 J  (1kJ = 1000 J)

Q' = mcΔT

generally, m = mass of the substance

c  = specific heat of the substance

ΔT = Change in temperature

Specific heat capacity of the product formed after mixing = c = 4.19 J/g°C

Mass of the resulting  mix = 300 g

ΔT = ?

1450 J=300g\times 4.19 J/g^oC\times \Delta T

\Delta T=\frac{1450 J}{300g\times 4.19 J/g^oC}

\Delta T=1.15^oC

1.15°C is the temperature increase.

8 0
1 year ago
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