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1 year ago

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A car is traveling at a constant speed of 46 miles per hour. the formula for the distance traveled at the end of t hours is d=46

t. Represent the distance at the end of 7,12, and 18 hours as ordered pairs in the form (t,d).

1 answer:

jonny [76]1 year ago

3 0

d = 46t

First, let's find "d" for 7 hours.

d = 46(7)

d = 322 miles (7, 322)

Next, let's find "d" for 12 hours.

d = 46(12)

d = 552 miles (12, 552)

Finally, let's find "d" for 18 hours.

d = 46(18)

d = 828 miles (18, 828)

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Answer:

a) Y 0 1 2

P(Y) 0.58 0.23 0.11

b) mean= 0.45, S.D= 0.6718

c) mean= 1.285, S.D= 8.74

Step-by-step explanation:

a) The following table shows the probability distribution of X:

X 0 1 2 3 4 or more

P(X) 0.58 0.23 0.11 0.05 0.03

Defect >2 = cannot be sold

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Y = defect that can be sold

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Probability distribution of the random variable Y:

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b) mean of Y (μ)

μ = Σ x*P(Y)

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= 0+0.23+0.22 = 0.45

Standard deviation of Y = σ

σ = Σ√(x-mean)^2*P(Y)

= Σ√[(x- μ )^2*P(Y)]

= √[(0-0.45)^2*0.58+ (1-0.45)^2*0.23 + (2-0.45)^2*0.11]

= √[0.11745 + 0.069575 +0.264275

= √(0.4513

σ = 0.6718

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σ for defect that be sold = 0.66

μ for defect that be sold = 0.40

Difference between μ of F and μ of G

= 0.45-0.40 = 0.05

Difference between σ of F and σ of G

= 0.67-0.66 = 0.01

Selling price of fat quarter without defect = $5

Discount per defect = $1.5

Selling price per defect = 5-1.5 = $3.5

Discount per 2 defect = $1.5*2 = $3

Selling price per defect = 5-3 = $2

Since defect to be sold cannot be greater than 2, let Y = 5,3,2

Probability distribution of the selling price Y:

Y 5 3 2

P(Y) 0.58 0.23 0.11

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σ = Σ√[(x- μ )^2*P(Y)]

σ = √[(5-1.285)^2*0.58+ (3-1.285)^2*0.23 + (2-1.285)^2*0.11]

σ = 8.00+0.68+0.06 = 8.74

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