June has a credit card balance of $4,350 that comes with a 19% APR. She would like to have the balance paid off in the next 8 mo
2 answers:
Answer:
b. $268.14
Step-by-step explanation:
Original credit card monthly payment =
where
Principal= $4350
i= 19/12/100=0.01583
n= 8
Putting the values in formula we get:
We get A1= $583.19
Now, she paid $2000 making new principle = $2350
i and n are same.
We get A2=315.06
Difference between A1 and A2=
Therefore, June lowered her minimum monthly payment by $268.13 close to option B.
Hence, option B is correct.
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First, we need to solve the differential equation.
This a separable ODE. We can rewrite it like this:
Now we integrate both sides.
We get:
When we solve for y we get our solution:
To find out if we have any horizontal asymptotes we must find the limits as x goes to infinity and minus infinity.
It is easy to see that when x goes to minus infinity our function goes to zero.
When x goes to plus infinity we have the following:
When you are calculating limits like this you always look at the fastest growing function in denominator and numerator and then act like they are constants.
So our asymptote is at y=8.
This a separable ODE. We can rewrite it like this:
Now we integrate both sides.
We get:
When we solve for y we get our solution:
To find out if we have any horizontal asymptotes we must find the limits as x goes to infinity and minus infinity.
It is easy to see that when x goes to minus infinity our function goes to zero.
When x goes to plus infinity we have the following:
When you are calculating limits like this you always look at the fastest growing function in denominator and numerator and then act like they are constants.
So our asymptote is at y=8.
Step-by-step explanation:
Given precision is a standard deviation of s=1.8, n=12, target precision is a standard deviation of σ=1.2
The test hypothesis is
H_o:σ <=1.2
Ha:σ > 1.2
The test statistic is
chi square =
=
=24.75
Given a=0.01, the critical value is chi square(with a=0.01, d_f=n-1=11)= 3.05 (check chi square table)
Since 24.75 > 3.05, we reject H_o.
So, we can conclude that her standard deviation is greater than the target.