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2 years ago

Sharon pays $98.75 for twenty-five 14-ounce boxes of Yummy flakes cereal. How much does on box of cereal cost

Mathematics

2 answers:

Viefleur [7K]2 years ago

5 0

Answer:

$3.95

Step-by-step explanation:

Vadim26 [7]2 years ago

5 0

$3.95

x will represent the cost of one box of cereal.

98.75 = 25x

We want to get x by itself on one side of the equation, so to cancel out the multiplication by 25, we need to divide by 25. Also, what we do on one side of the equation, we must do to the other side. So, divide both sides of the equation by 25.

3.95 = x

So, one box of cereal costs $3.95.

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What is the value of x? Enter your answer as a decimal to the nearest tenth in the box.

gogolik [260]

ANSWER

23.6 feet

EXPLANATION

The given triangle is a right triangle.

The hypotenuse is 27 ft.

The given angle I s 29°

The unknown side x, is adjacent to the given angle.

We use the cosine ratio to get,

$\cos(29 \degree) = \frac{adjacent}{hypotenuse}$

$\cos(29 \degree) = \frac{x}{27}$

We multiply both sides by 27 to get;

$x = 27\cos(29 \degree)$

$x = 23.6ft$

to the nearest tenth.

7 0

1 year ago

Read 2 more answers

Consider the following equation, bh+hr=25 when solving for r

Komok [63]

Solve for r.

You want to get r by itself on one side on the equal sign.

bh + hr = 25

Subtract bh from both sides.

hr = 25 - bh

Divide h on both sides.

r = 25 - bh / h

The two h's cancel each other out.

r = 25 - b

Hope this helps!

4 0

2 years ago

Read 2 more answers

A caterer charges a $65 equipment fee to set up for a party and $9.50 per p person for food served at the party. Which of the fu

AleksAgata [21]

Answer:

The total cost function of having a party catered is f(p) = 65 + 9.50 p

Step-by-step explanation:

The equipment fee of the caterer = $65

The charge per plate = $9.50

Let, Total number of people invited in the party = p

So, the cost of plates of p people = Number of people x Per plate cost

= p x $9.50

Now, Total Catering Cost = Equipment Fee + Cost of all plates

or, Total cost = $65 + p x $9.50

Hence, the total cost function of having a party catered

is f(p) = 65 + 9.50 p.

3 0

2 years ago

A rectangular pool 18 meters by 12 meters is surrounded by a walkway of width x

vesna_86 [32]

Answer:

x=3 meters

Step-by-step explanation:

step 1

Find the area of the rectangular pool

$A=LW$

we have

$L=18\ m\\W=12\ m$

substitute

$A=18(12)=216\ m^2$

step 2

Find the area of rectangular pool including the area of the walkway

Let

x ----> the width of the walkway

we have

$L=(18+2x)\ m\\W=(12+2x)\ m$

substitute

$A=(18+2x)(12+2x)$

step 3

Find the area of the walkway

To find out the area of the walkway subtract the area of the pool from the area of rectangular pool including the area of the walkway

$A=(18+2x)(12+2x)-216$

step 4

Find the value of x if the area of the walkway equal the area of the pool

$(18+2x)(12+2x)-216=216$

Solve for x

$(18+2x)(12+2x)=432\\216+36x+24x+4x^{2}=432\\4x^{2} +60x-216=0$

Solve the quadratic equation by graphing

The solution is x=3 meters

see the attached figure

8 0

2 years ago

1) A family consisting of three persons—A, B, and C—goes to a medical clinic that always has a doctor at each of stations 1, 2,

crimeas [40]

Answer:

Step-by-step explanation:

Let us record the station number 1, 2 or 3 for each family member A, B or C.

I am attaching a table containing total outcomes. Outcomes are presented along rows while the assigned station to each member is written along columns. For ease of understanding, 1 3 2 in the table should be interpreted as family member A being assigned to station 1, member B to station 3 and member C to station number 2, respectively.

From table it is clear that the total outcomes possible are 27.

We know that, probability can be defined as,

$PROBABITILY = \frac{NUMBER\;OF\;DESIRED\;OUTCOMES}{TOTAL\;NUMBER\;OF\;OUTCOMES}$

a) All Members Assigned to the Same Station.

Cases for all members being assigned to same station are as follows:

[1 1 1], [2 2 2], [3 3 3] (outcome number 1, 14 and 27 in the table).

Therefore,

$PROBABILITY\;(Case\;a) = \frac{3}{27}\\\\PROBABILITY\;(Case\;a) = 0.111$

b) At Most Two Members Assigned to the Same Station.

It means that maximum of 2 members can have the same station. Cases for this situation are as follows:

[1 1 2], [1 1 3], [1 2 1], [1 2 2], [1 3 1], [1 3 3], [2 1 1], [2 1 2], [2 2 1], [2 2 3], [2 3 2],

[2 3 3], [3 1 1], [3 1 3], [3 2 2], [3 2 3], [3 3 1], [3 3 2]

(outcome number 2, 3, 4, 5, 7, 9, 10, 11, 13, 15, 17, 18, 19, 21, 23, 24, 25 and 26 in the table).

Therefore,

$PROBABILITY\;(Case\;b) = \frac{18}{27}\\\\PROBABILITY\;(Case\;b) = 0.666$

c) All Members Assigned to a Different Station.

For this scenario, we have the following results:

[1 2 3], [1 3 2], [2 1 3], [2 3 1], [3 1 2], [3 2 1] (outcome number 6, 8, 12, 16, 20 and 22 in the table).

Therefore,

$PROBABILITY\;(Case\;c) = \frac{6}{27}\\\\PROBABILITY\;(Case\;c) = 0.222$

3 0

2 years ago