The mean is 85*0.39 = 33.15, while the standard error is sqrt(0.39*0.61/85) = 0.0529. Using the z-score of 1.96, the confidence interval is:33.15 +/- 1.96*0.0529 = (33.05, 33.25)By dividing by 85, this corresponds to a proportion of:(0.3888, 0.3912)
G= 48/4???? that would make sense wouldn't it? because 48/4 would be the total number of points divided by the amount of games in which those points are scored.
*Hint: In order to find the coordinates, you plug in the coordinates into the rule and solve.
(x, y) → (x + 2, y - 8)
(4, -5) → (4 + 2, -5 - 8)
(6, -13)
The coordinates of B' is (6, -13).
Answer:
a rotation 90˚ clockwise and then a reflection across the y-axis
Step-by-step explanation:
I'm doing the test right now
Answer:
95% of the text messages have length between 23 units and 47 units.
Step-by-step explanation:
We are given the following in the question:
The lengths of text messages are normally distributed.
95% confidence interval:
(23,47)
Thus, we could interpret the confidence interval as:
About 95% of the text messages have length between 23 units and 47 units.
By Empirical rule for a normally distributed data, about 95% of data lies within 2 standard deviations of mean , thus we can write:

Thus, the mean length of text messages is 23 units and standard deviation is 6 units.