A line segment has endpoints at (–4, –6) and (–6, 4). Which reflection will produce an image with endpoints at (4, –6) and (6, 4
)?
2 answers:
Answer:
Reflection on x - axis.
Step-by-step explanation:
A line segment has two endpoints at A ( -4, -6 ) and B ( -6, 4 ).
Here point A lies in third quadrant and B lies in second quadrant.
Now we have to find the kind of reflection was done so that new points became A' (4, -6) and B' (6, 4)
a' is lying in fourth and B' is in first quadrant.
Therefore, segment AB which is parallel to y axis when reflected on x-axis, became A' B'.
So reflection about y-axis is the answer.
You might be interested in
Answer:
The constant of variation is $1.50
Step-by-step explanation:
Given
Point 1 (1,2)
Point 2 (5,8)
Required
Constant of Variation
Though the graph would have assisted in answering the question; its unavailability doesn't mean the question cannot be solved.
Having said that,
the constant variation can be solved by calculating the gradient of the graph;
The gradient is often represented by m and is calculated as thus
Where
By substituting values for x1,x2,y1 and y2; the gradient becomes
Hence, the constant of variation is $1.50