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Ierofanga [76]
2 years ago
5

In the xy plane, a quadrilateral has vertices at (-1, 4), (7,4), (7,5), and (-1. 5). What is the perimeter of the quadrilateral?

(A) 17 (B) 18 (C) 19 (1) 32 (E) 34

Mathematics
1 answer:
iris [78.8K]2 years ago
8 0

Answer:

(B) 18.

Step-by-step explanation:

We are asked to find the perimeter of a quadrilateral with vertices at (-1, 4), (7,4), (7,5), and (-1. 5).

First of all, we will draw vertices of quadrilateral on coordinate plane and connect the vertices as shown in the attached photo.

We can see that our quadrilateral is a parallelogram, whose parallel sides are equal.

\text{Perimeter of quadrilateral}=8+1+8+1

\text{Perimeter of quadrilateral}=16+2

\text{Perimeter of quadrilateral}=18

Therefore, the perimeter of the given quadrilateral is 18 units.

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Caleb solved this equation and recorded his work. 7.4x + 4.1(2x − 4) = −2.3(x − 6) − 21.6 1. 7.4x + 8.2x − 16.4 = −2.3x + 13.8 −
IRINA_888 [86]
For this case we have the following equation:
 7.4x + 4.1 (2x - 4) = -2.3 (x - 6) - 21.6

 Step 1 of the solution is to make the distributive property.
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 7.4x + 8.2x - 16.4 = -2.3x + 13.8 - 21.6

 Step 1 is correct.
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 Answer:
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A = FV - OV/T for OV
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we have that

A = FV - OV/T

solve for OV


Multiply both sides by T

A*T =T* FV - T*(OV/T)

A*T =T* FV - OV


Add OV to both sides

OV+ A*T =T* FV - OV +OV

OV+ A*T =T* FV


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