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2 years ago

6

Mr. Brent uses 1/4 cup of blue paint and 1/4 cup of yellow paint to make each patch of green paint. How many batches of green pa

int can he make with the amount of the paint left? Explain ( amount left 3cups of Blue anf 4 cups of yellow

2 answers:

harina [27]2 years ago

6 0

12 batches of green paint

Nata [24]2 years ago

4 0

12 batches:D hope I helped

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A study was conducted to determine the mean birth weight of a certain breed of kittens. Consider the birth weights of kittens to

kipiarov [429]

3.56 +/- 0.011 = ( 3.549, 3.571). This is the answer.

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2 years ago

The flathead rail tunnel in Montana is about 7 3/4 miles long. A train travels at a speed of 3/4 mile per mile minute.how long w

kogti [31]

7 3/4 × 3/4 = So u add 3×3=9
Then add 4×4=16 Give you 9/16
Then you add that 7 you left out with 9/16
But just the 9 not the 16
7 × 9 = 63 And your answer is 63/16
Hope i help :-)

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2 years ago

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Write an inequality for the situation. all real numbers at most –9.5 or at least 5.5

Tomtit [17]

Hello,

If b represents any real number,

b<=-9.5
or
5.5<=b

Answer C

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2 years ago

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Solve. A power outage affected all homes and businesses within a 3 mile radius of the power station. If the power station is loc

Aneli [31]

Answer:

$\left ( x+5 \right )^{2}+\left ( y-6 \right )^{2}= 9$

Step-by-step explanation:

The power station is located 5 miles west and 6 miles north of the center of town. So if we try to locate the above points on a Cartesian plane. The co-ordinates of these points will be (-5,6).

And it is also mentioned that a power outage affected all homes and businesses within a 3 mile radius of the power station. So if we plot all the furthest points from the station affected by the power outage it will be a circle of radius 3 miles and center at (-5,6).

The equation of a circle with center (a,b) and radius r is given by :

$\left ( x-a \right )^{2}+\left ( y-b \right )^{2}= r^{2}$

Hence the equation of the resulting circle will be: $\left ( x+5 \right )^{2}+\left ( y-6 \right )^{2}= 3^{2}$

4 0

2 years ago

Dustin is standing at the edge of a vertical cliff, 40 meters high, which overlooks a clear lake. He spots a fluffy white cloud

Licemer1 [7]

Answer:

53.33 meters

Step-by-step explanation:

Let AB represents the height of the cliff,

( where, A is top and B is bottom ),

Also, C and D represents the shadow of the cloud and cloud in the sky respectively,

Suppose E is a point in the segment CD,

Such that,

AB = DE = 40 meters,

According to the question,

$m\angle CAE = 30^{\circ}$

$m\angle EAD = 60^{\circ}$

Since,

$\tan =\frac{\text{Perpendicular}}{\text{Base}}$

$\implies \tan 60^{\circ}=\frac{DE}{AE}$

$\sqrt{3}=\frac{40}{AE}$

$\implies AE = \frac{40}{\sqrt{3}}$

Now,

$\tan 30^{\circ}=\frac{CE}{AE}$

$\frac{1}{\sqrt{3}}=\frac{\sqrt{3}CE}{40}$

$\implies CE = \frac{40}{3}$

Hence,

The height of the cloud above the lake = CE + ED

$=\frac{40}{3}+40=13.33+40 = 53.33\text{ meters}$

3 0

2 years ago