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adell [148]
2 years ago
6

Sonya and Isaac are in motorboats located at the center of a lake. At time t=0, Sonya begins traveling south at a speed of 36 mp

h. At the same time, Isaac takes off, heading east at a speed of 27mph. How fast is the distance between them changing after 12 minutes?
Mathematics
1 answer:
Rashid [163]2 years ago
6 0

Answer:

the speed btn sonya and issac would make a right angled trangle hence easy 2 solve through pythogoras

{36}^{2}  +  {27}^{2}  = 2025

then find the

\sqrt[?]{?}

hence get 45

since it was 12 mins we need 2 multiply by 12

hence

45 \times 12 = 540

Therefore it's 540mph

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Let x be unknown number. If number x is multiplied by -\dfrac{2}{3} and the product is equal to \dfrac{3}{4}, then

x\cdot \left(-\dfrac{2}{3}\right)=\dfrac{3}{4}.

To find x you should divide \dfrac{3}{4} by -\dfrac{2}{3}:

x=\dfrac{\dfrac{3}{4}}{-\dfrac{2}{3}}=\dfrac{3}{4}\cdot \left(-\dfrac{3}{2}\right)=-\dfrac{3\cdot 3}{4\cdot 2}=-\dfrac{9}{8}.

Answer: x=-\dfrac{9}{8}

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The graph of which function is decreasing over the interval (–4, ∞)?
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I think second must b the answee
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2 years ago
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The batting Wang Xiu Ying uses to fill quilts has a thermal conductivity rate of 0.030.030, point, 03 watts (\text{W})(W)left pa
Semenov [28]

Answer:

Step-by-step explanation:

The question is incomplete. Here is the complete question.

the batting wang xiu ying uses to fill quilts has a thermal conductivity rate of 0.03 watts (W) per meter(m) per degree celsius. what is the batting thermal conductivity when w/cm•c

Given

K = 0.03W/m°C

Required

Convert K to W/cm°C

Since 1m = 100cm,

K = 0.03w/1×100cm°C

K = 3×10^-2w/10² cm°C

K = 3 × 10^-2w/10² cm°C

K = 3w× 10^{-2-2}cm°C

K = 3w×10^-4cm°C

K = 0.0003w/cm°C

8 0
1 year ago
The GPA of accounting students in a university is known to be normally distributed. A random sample of 20 accounting students re
Vladimir79 [104]

Answer:

The 95% of confidence intervals

(2.84 ,2.99)

Step-by-step explanation:

A random sample of 20 accounting students results in a mean of 2.92 and a standard deviation of 0.16

given small sample size n =20

sample mean x⁻ =2.92

sample standard deviation 'S' =0.16

level of significance ∝ =  0.95

The 95% of confidence intervals

x^{-}  ± t_{\alpha } \frac{S}{\sqrt{n} }

the degrees of freedom γ=n-1 =20-1=19

t-table 2.093

(x^{-}  - t_{\alpha } \frac{S}{\sqrt{n} },x^{-}  + t_{\alpha } \frac{S}{\sqrt{n} })

(2.92 - 2.093(\frac{0.16}{\sqrt{20} } ,2.92+2.093(\frac{0.16}{\sqrt{20} } )

(2.92-0.0748,2.92+0.0748)

(2.84 ,2.99)

Therefore the 95% of confidence intervals

(2.84 ,2.99)

4 0
2 years ago
If line b is perpendicular to line a, and line c is perpendicular to line a, what is the slope of line c?
slega [8]

we know that

If line b is perpendicular to line a, and line c is perpendicular to line a,

then

line b and line c are parallel

and two lines parallel have the same slope

so

<u>Find the slope of the line b</u>

Let

A(-3,-2)\\B(2,3)

The formula to calculate the slope between two points is equal to

m=\frac{(y2-y1)}{(x2-x1)}

(x1,y1)=(-3,-2)\\(x2,y2)=(2,3)

substitute

m=\frac{(3+2)}{(2+3)}

m=\frac{(5)}{(5)}

m=1

therefore

<u>the answer is</u>

<u>the slope of the line c is</u>

mc=1

8 0
2 years ago
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