Question

The curvature of the Tacoma Narrows Bridge in

Answer 1

Answer:

Width of the arch = 105 m

Step-by-step explanation:

Function representing the width of the arch,

f(x) = -0.016(x - 52.5)² + 45

where x = width of the base of the arch or horizontal distance from arch's left end

f(x) = vertical distance of the arch

From the given quadratic function, vertex of the parabola is (52.5, 45).

Coordinates of the vertex represents,

Height of the arch = 45 m

Half of the horizontal distance from the left end = 52.5 m

Therefore, width of the bridge = 2(Half the width of the bridge from left end) = 2×52.5

= 105 m

Therefore, given bridge is 105 m wide.