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2 years ago

5

HELP!!!! 2 dot plots. Both number lines go from 0 to 10. Plot 1 is titled fifth grade. There are 2 dots above 1, 3 above 2, 1 ab

ove 3, 4 above 4, 5 above 5, 5 above 6, 2 above 7, 2 above 8, 0 above 9, 0 above 10. Plot 2 is titled seventh grade. There are 2 dots above 0, 2 above 1, 3 above 2, 5 above 3, 5 above 4, 3 above 5, 3 above 6, 1 above 7, and 0 above 8, 9, and 10.
The dot plot shows the number of hours, to the nearest hour, that a sample of 5th graders and 7th graders spend watching television each week. What are the mean and median?

The 5th-grade mean is
.

The 7th-grade mean is
.

The 5th-grade median is
.

The 7th-grade median is
.

2 answers:

Elis [28]2 years ago

7 0

Answer:

5th grade mean - 4.67

7th grade mean - 3.46

5th-grade median - 5

7th-grade median - 3.5

Annette [7]2 years ago

4 0

Answer:

5th grade mean - 4.67

7th grade mean - 3.46

5th-grade median - 5

7th-grade median - 3.5

Step-by-step explanation:

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Audrey has 400 songs on her MP3 player. Of these songs, 150 are by female vocalists, 75 are by male vocalists, and 175 are by gr

Nuetrik [128]

Probability for male = 75/400 = 3/16

Probability for groups = 175/400 = 7/16

Probability for female = 150/400 = 3/8

There is a 3/8 probability of the song being sung by a female vocalist.

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7 0

2 years ago

The mean weight of newborn infants at a community hospital is 6.6 pounds. A sample of seven infants is randomly selected and the

Lera25 [3.4K]

Answer:

The correct option is A

Step-by-step explanation:

From the question we are told that

The population is $\mu = 6.6$

The level of significance is $\alpha = 5\% = 0.05$

The sample data is 9.0, 7.3, 6.0, 8.8, 6.8, 8.4, and 6.6 pounds

The Null hypothesis is $H_o : \mu = 6.6$

The Alternative hypothesis is $H_a : \mu > 6.6$

The critical value of the level of significance obtained from the normal distribution table is

$Z_{\alpha } = Z_{0.05 } = 1.645$

Generally the sample mean is mathematically evaluated as

$\=x = \frac{\sum x_i }{n}$

substituting values

$\=x = \frac{9.0 + 7.3 + 6.0+ 8.8+ 6.8+ 8.4+6.6 }{7}$

$\=x = 7.5571$

The standard deviation is mathematically evaluated as

$\sigma = \sqrt{\frac{\sum [ x - \= x ]}{n} }$

substituting values

$\sigma = \sqrt{\frac{ [ 9.0-7.5571]^2 + [7.3 -7.5571]^2 + [6.0-7.5571]^2 + [8.8- 7.5571]^2 + [6.8- 7.5571]^2 + [8.4 - 7.5571]^2+ [6.6- 7.5571]^2 }{7} }$ $\sigma = 1.1774$

Generally the test statistic is mathematically evaluated as

$t = \frac{\= x - \mu } { \frac{\sigma }{\sqrt{n} } }$

substituting values

$t = \frac{7.5571 - 6.6 } { \frac{1.1774 }{\sqrt{7} } }$

$t = 1.4274$

Looking at the value of t and $Z_{\alpha }$ we see that $t < Z_{\alpha }$ hence we fail to reject the null hypothesis

What this implies is that there is no sufficient evidence to state that the sample data show as significant increase in the average birth rate

The conclusion is that the mean is $\mu = 6.6 \ lb$

8 0

2 years ago

Please help! Tim and Jane both work at a company that sells boxes of breakfast cereal. The boxes of cereal cost £3.00 and the am

patriot [66]

Answer: Jane needs to reduce the price by 20%

Step-by-step explanation: The first thing to note is the original price of the cereal and that is given as £3 for every 160 grams.

The change proposed by Tim is as follows;

Put 25% more cereal in the box (and do not change the price). That means 160 g plus 25%. Mathematically, this can be expressed as;

New weight = 160 + (160 * 25%)

New weight = 160 + (160 * 0.25)

New weight = 160 + 40

New weight = 200

Hence, Tim's idea would result in a cereal box with 200 grams that still cost £3. At this rate, each gram would cost

1 gram = Price / Total grams

1 gram = 3/200

1 gram = 0.015

However, Jane has proposed that the amount of cereal in the box should not be changed, which means the box of cereals should remain 160 grams. The price should be reduced to give the same value as Tim's idea. This means 160 g of cereals should now sell for £0.015 per gram. That would bring the price of 160 g to,

1 gram = 0.015

160 grams = 0.015 * 160

160 grams = 2.4

With Jane's proposal, a 160 g box of cereal should now be sold at £2.4 each. That is a reduction of £0.6

Therefore, the percentage reduction can be calculated as follows;

% decrease = (0.6/3) * 100

% decrease = (1/5) * 100

% decrease = 20

From the results above, Jane should reduce the price (£3 per 160 g) by 20%.

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3 years ago

Which expression correctly represents “nine less than the quotient of a number and four, increased by three

Natasha2012 [34]

The required expression is $\frac{x}{4}-9+3$

Step-by-step explanation:

We need to identify the expression correctly represents “nine less than the quotient of a number and four, increased by three"

Solving:

Let the number is x

The quotient of number and four: $\frac{x}{4}$

nine less than the quotient of a number and four: $\frac{x}{4}-9$

Increased by 3 : $\frac{x}{4}-9+3$

So, nine less than the quotient of a number and four, increased by three is:

$\frac{x}{4}-9+3$

So, The required expression is $\frac{x}{4}-9+3$

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3 0

2 years ago

The thrill of riding a roller coaster is addictive, both for its users who take the ride, and for the designers and engineers

Makovka662 [10]

Answer:

The quantitative variables in this case are:

A. Speed

D. GForce

E. Height

G. Duration

H. Numinversions

J. Length

Step-by-step explanation:

One criteria to differentiate qualitative variables from quantitative variables is to determine if mathematical calculations over these variables makes sense.

If it makes sense, it is a quantitative variable.

For example, binary variables, although they can be represented by 0 and 1, would be a qualitative variable.

The quantitative variables in this case are:

A. Speed

D. GForce

E. Height

G. Duration

H. Numinversions

J. Length

They all will be represented by numbers for which mathematical operations make sense.

6 0

2 years ago