Answer:
P(t) = 1000e^(0.01155)t
Step-by-step explanation:
Let the population of barangay be expressed according to the exponential formula;
P(t) = P0e^kt
P(t) is the population of the country after t years
P0 is the initial population
t is the time
If barangay has 1000 initially, this means that P0 = 1000
If the population doubles after 60years then;
at t = 60, P(t) = 2P0
Substitute into the formula
2P0 = P0e^k(60)
2 = e^60k
Apply ln to both sides
ln2 = lne^60k
ln2 = 60k
k = ln2/60
k = 0.01155
Substitute k = 0.01155 and P0 into the expression
P(t) = 1000e^(0.01155)t
Hence an exponential model for barangay's population is
P(t) = 1000e^(0.01155)t
The correct answer is choice D. If you put choice D into words, it is saying 30% (0.3) of the total is 12 minutes.
To solve this, use inverse operations.
<span><u>0.3m</u> = <u>12</u>
</span>0.3 0.3
m = 40
It will take Beck 40 minutes.
The correct answer is C. 1.5
You can find this answer by using any of the points on the graph and putting them into the given equation. Then you can solve for the constant. For the purpose of this example, we will use (10, 15)
Height = Constant * Width ---> Plug in known values.
15 = Constant * 10 ----> Divide both sides by 10
1.5 = Constant
This will work with whatever numbers you use from the graph. Although this graph does not have any others to really choose from.
Answer:
Step-by-step explanation:
From the question, we can form an equation like: S = 7200 + 350X
where S is the salary and X is year.
1. His salary in the 9th year, means X=9, so we substitute 9 into the equation to find S = 7200 +350 (9) = 10350
2. The total he will have in the first 12years, we have:
Sum of first n terms of an <em><u>AP: S =(n/2)[2a + (n- 1)d]</u></em> where a is the value of the 1st term, here a is 7200 and d = 350 the common difference between terms
=> S = (12/2)[2*7200 + (12- 1)350] = 109500
