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irinina [24]
1 year ago
13

Bethany can mow her family’s lawn in 4 hours. Her brother Colin can mow the lawn in 3 hours. Which equation can be used to find

x, the amount of time it would take for Bethany and Colin to mow the lawn together?
Mathematics
2 answers:
Hitman42 [59]1 year ago
7 0

Answer:

c

Step-by-step explanation:

Brut [27]1 year ago
3 0
The answer to this question is C
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How many pairs of whole numbers have a sum of 110
kap26 [50]

There are different definitions of "whole numbers".

Some define it as an integer (i.e. positive or negative) [some dictionaries]

Some define it as a non-negative integer. [most math definitions]

We will take the math definition, i.e. 0<= whole number < &infin;

To find pairs (i.e. two) whole numbers with a sum of 110, we start with

0+110=110

1+109=110

2+108=110

...

54+56=110

55+55=110

Since the next one, 56+54=110 is the same pair (54,56) as 54+56=110, we stop at 55+55=110  for a total of 56 pairs.

5 0
1 year ago
The manager of a symphony in a large city wants to investigate music preferences for adults and students in the city. Let pA rep
monitta

Answer:

Answer E

Step-by-step explanation

The statement gives a probability of approximately 0.022 for the difference in sample proportions, pˆA−pˆS, being greater than 0.

6 0
1 year ago
There are 11 portable mini suites (a.k.a. cages) in a row at the Paws and Claws Holiday Pet Resort. They are neatly labeled with
BigorU [14]

Step-by-step explanation:

a) 7!

If there are no restrictions, answer is 7! as it is the permutation of all animals.

b) 4! x 3!

As cats are 6 and Dogs are 5, thus 1st and last must be cats in order to have alternate arrangements. Therefore the only choices are the order of the cats among  themselves and the order of the dogs among themselves. There are 4! permutations of the cats and 3! permutations of the dogs, so there are a total of 4! x 3! possible arrangements of the suites.

c) 3! x 5!

There are 3! possible arrangements of  the dogs among themselves. Now, if we consider the dogs as  one ”object” together, then we can think of arranging the 4 cats  together with this 1 additional object. There are 5! such arrangements possible, so there are a total of 3! · 5! possible arrangements of the suites.

d) 2 x 4! x 3!

As required that all the cats must be together and all the dogs must be together, either the cats are all  before the dogs or the dogs are all before the cats. There are two possible arrangements thus two times of both possibilities is the answer i.e.  2 x 4! x 3!

3 0
2 years ago
what is the distance around a triangle that has sides measuring 2 1/8 feet, 3 1/2 feet, and 2 1/2 feet?
Vlad1618 [11]
7 and 1/8. all you need to do is add these together by getting a common denominator of eight
5 0
1 year ago
Read 3 more answers
Gerry wants to construct a triangle with segments that are 4, 6, and 11 inches long. Is his triangle possible? Explain how you k
Margarita [4]

Answer:

No

Step-by-step explanation:

Because, the Pythagorean Inequality Theorem states that the two smallest angles should add up to be more than the third angle.

4+6=10  

11 is bigger than 10, still.

Therefore, no the triangle is not possible.

3 0
1 year ago
Read 2 more answers
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