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1 year ago

14

the mean height of the team is 200.3 .a new player joins and raises the mean average height to 201cm. work out the height of the

new player.

1 answer:

ivann1987 [24]1 year ago

8 0

Question

The table shows the heights in a basketball team.

Height: 198, 199, 200, 201, 202

a.) Work out the mean height of the team. Round you answer to 1d.p.

That, I have worked out is 200.3

b.) A new player joins the team and raises the mean average height to 201cm. Work out the height of the new player.

Answer:

206 cm

Step-by-step explanation:

The sum of the fiven numbers, 198+199+200+201+202=1000

For a mean of 201, the product should be 201*6=1206

The difference of the two is equivalent to the height of the other person hence 1206-1000=206 cm

Therefore, the height is 206 cm

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2 years ago

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Imaginá que tenés 125 dados cúbicos del mismo tamaño ¿Cuantos dados de altura tiene el cubo de mayor tamaño que podés armar apil

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Answer:

(i) Debemos apilar 5 dados para construir el cubo de mayor tamaño.

(ii) Se necesita 121 dados cuadrados para formar el cuadrado con la mayor cantidad de dados posibles, quedando 4 dados sobrantes.

Step-by-step explanation:

(i) Sabemos por la Geometría Euclídea del Espacio que un cubo es un sólido regular con 6 caras cuadradas y longitudes iguales. Cada dado tiene un volumen de 1 dado cúbico y 125 dados dan un volumen total de 125 dados cúbicos.

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$V = L^{3}$

Donde:

$L$ - Longitud de la arista, medida en dados.

$V$ - Volumen del cubo, medido en dados cúbicos.

Ahora, necesitamos despejar la longitud de la arista para calcular la altura máxima posible:

$L = \sqrt[3]{V}$

Dado que $V = 125\,dados^{3}$ , encontramos que la altura del cubo de mayor tamaño sería:

$L =\sqrt[3]{125\,dados^{3}}$

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$A = L^{2}$

Donde:

$L$ - Longitud de arista, medida en dados.

$A$ - Área, medida en dados cuadrados.

Puesto que la longitud de arista se basa en un conjunto discreto, esto es, el número de dados disponibles, debemos encontrar el valor máximo de $L$ tal que no supere 125 y de un área entera. Es decir:

$L \leq 125\,dados$

Si cada cubo tiene un área de 1 dado cuadrado, entonces un cuadrado conformado por 125 dados tiene un área total de 125 dados cuadrados. Entonces:

$L^{2}< 125\,dados^{2}$

Esto nos lleva a decir que:

$L < 11.180\,dados$

Entonces, la longitud máxima del cuadrado con la mayor cantidad de cubos posible es de 11 dados. El número total requerido de cubos es el cuadrado de esa cifra, es decir:

$n = (11\,dados)^{2}$

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Se necesita 121 dados cuadrados para formar el cuadrado con la mayor cantidad de dados posibles, quedando 4 dados sobrantes.

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2 years ago

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2 years ago

Darcie wants to crochet a minimum of 3 blankets. Darcie crochets at a rate of 1/15 of a blanket a day. She has 60 days until she

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Answer:

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Step-by-step explanation:

The complete question is:

Darcie wants to crochet a minimum of 3 blankets to donate to a homeless shelter. Darcie crochets at a rate of 1/15 of a blanket per day. She has 60 days until when she wants to donate the blankets, but she also wants to skip crocheting some days so she can volunteer in other ways. Write an inequality to determine the number of days, s, Darcie can skip crocheting and still meet her goal.

Solution:

Given:

Darcie wants to crochet a minimum of 3 blankets to donate.

Rate at which she crochet = $\frac{1}{15}$ of a blanket per day.

Maximum number of days she has = 60.

To find the number of days Dancie can skip out of 60 days and still reach her goal.

Let $s$ represent the number of days she can skip.

Number of days left to crochet = $(60-s)$ days

At rate of $\frac{1}{15}$ of a blanket per day, number of blankets Dancie can corchet in $(60-s)$ days can be given as :

⇒ $\frac{1}{15}(60-s)$

Simplifying using distribution.

⇒ $(\frac{1}{15}.60)-(\frac{1}{15}.s)$

⇒ $4-\frac{s}{15}$

Dancie needs to crochet a minimum of 3 blankets to reach her goal.

Thus, the inequality can be given as:

$4-\frac{s}{15}\geq 3$

Solving the inequality for $s$

Subtracting 4 both sides.

$4-4-\frac{s}{15}\geq 3-4$

$-\frac{s}{15}\geq -1$

Multiplying both sides by -15.

$-15(-\frac{s}{15})\leq -15(-1)$ [On multiplying by a negative number the sign of inequality reverse]

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5 0

2 years ago