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Alisiya [41]
1 year ago
14

A company purchased a delivery van for $28,000 with a salvage value of $3,000 on September 1, Year 1. It has an estimated useful

life of 5 years. Using the straight-line method, how much depreciation expense should the company recognize on December 31, Year 1?
Mathematics
1 answer:
Tems11 [23]1 year ago
4 0

Answer:

Depreciation till December 31, Year 1 will be equal to 1,250$

Step-by-step explanation:

Purchasing Cost = 28,000$

Salvage Value = 3,000$

Total Depreciation:

Total Depreciation over 5 years (60 Months) = Purchasing Cost - Salvage Value

Total Depreciation over 5 years (60 Months) = 28,000 - 3,000

Total Depreciation over 5 years (60 Months) = 25,000$

Monthly Depreciation:

Using the unity method we have monthly depreciation by dividing the total depreciation by the total no. of months as below:

Total Depreciation over a single month =25,000/60

Total Depreciation over a single month = 416.67$ (Monthly Depreciation)

Depreciation till December 31, Year 1

As from September 1, Year 1 to December 31, Year 1, its been 3 months therefore total depreciation will be = 3 * Monthly Depreciation

Depreciation till December 31, Year 1 = 3 * 416.67

Depreciation till December 31, Year 1 = 1,250$

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Answer:

apart from using the hoc to predict the college students gpa, some other variables can be used

1. the students intelligent quotient

2. ability to remember

3. study time

4. gym practice

Step-by-step explanation:

<u>1. the students intelligent quotient</u>

<u>gpa</u><u> </u>has a positive relationship with iq. they are both directly related. The more the iq of a a student, the greater is his ability to understand and have a good gpa. the slope will therefore be positive and be in an upward direction.

2. <u>ability to remember</u>

the gpa of students who have a good ability to remember but do not have a good grasp of the subject may not be high. the slope would be in a slightly upward direction

3. <u>study time</u>

gpa and practice have a positive relationship. the more a student studies, the more likelihood exists of having a better gpa. the slope would be upward bound.

4. <u>gym</u><u> </u><u>practice</u>

gpa and gym practice are not related so the slope would be in a downward direction.

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At the We-Pack Shipping, the workers can unload 28 trucks in 7 hours. Which of the following is a correct unit rate for this sit
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1 year ago
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Which statements are true regarding triangle LMN? Check all that apply.
dimaraw [331]

Answer:

NM = x

LM = x\sqrt{2}

tan (45) = 1

Step-by-step explanation:

Step 1: Pythagoras Theorem

Pythagoras theorem relates the three sides of the triangle in such a way that the sum of the square of base and perpendicular is equal to hypotenuse, such as:

                                        LM^{2} =LN^{2} +NM^{2}

Step 2: Trigonometric Functions

Only for a right angle triangle following three trigonometric relations are valid

                                        sin (\theta) = \frac{opposite}{hypotenuse}

                                        cos (\theta) = \frac{adjacent}{hypotenuse}

                                    tan (\theta)=\frac{sin (\theta)}{cos (\theta)} = \frac{opposite}{adjacent}

Step 3: Verifying all the possible answers

A: Since, LN = x and using tan (45) =1

we can calculate

                                              tan (\theta)= \frac{opposite}{adjacent}

                                           tan (45)= \frac{NM}{x} =1

therefore, NM = x (true)

B: As NM = x therefore it can not be equal to x\sqrt{2\\}.

C: Using Pythagoras Theorem

                                        LM^{2} =LN^{2} +NM^{2}

                                           LM^{2} =x^{2} +x^{2}

                                              LM^{2} =2x^{2}

                                         LM = \sqrt{2x^{2}} = x\sqrt{2}

It can also be proved using trigonometric relation

                                           cos (45) = \frac{x}{LM}

                                            LM = \frac{x}{cos (45)}

As, \frac{1}{cos (45)}= \sqrt{2}

Therefore

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D and E:

Using same approach similar to part A

Since, LN = x and NM = x

we can calculate

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                                           tan (45)= \frac{x}{x} =1

Therefore, tan (45) = 1  and not equal to \frac{\sqrt{2} }{2}

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