1. For multiplication and division), we first compare the number of significant figure (let's call it SF later in the problem) that the factors have. The product will have the least numbers between them. So, for the case of 11.55 x 2.5, 11.55 has 4 SF while 2.5 has 2. So we choose the smallest which is 2 for this case. Hence, the answer is B.
2. Using the same rules as mentioned in Item 1, we first compare the number of SF in the numbers give. 975.0321 has 7 SF while 0.0003 has 1 (all zeroes not following a counting number are not significant). We now solve for the quotient and round it off to 1 SF.
(975.0321/0.0003) = 3250107. Rounding it off, we have 3000000 or 3 x 10⁶. Thus, the answer is D.
3. The rules for multiplication still apply even for more than two factors. So, let's first take note of the SF present in each factor as shown below.
0.00147 = 3 SF
8.314 = 4 SF
7.100 = 4 SF (zeroes after a counting number in the decimal place are considered significant)
From this, we can see that the product must round off to 3 SF. Multiplying the three numbers, we have
0.00147 x 8.314 x 7.100 = 0.086773218
So, the product rounded off to 3 SF is 0.0868 or 8.68 x 10⁻². So, the answer must be C<span>.
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Answer:
The number of once is 9.1
The number of hundreds is 8.9
Step-by-step explanation:
Given as :
The total of digits having ones and hundreds = 900
The sum of digits = 18
Let The number of ones digit = O
And The number of hundreds digit = H
So, According to question
H + O = 18 .........1
100 × H + 1 × O = 900 ........2
Solving the equation
( 100 × H - H ) + ( O - O ) = 900 - 18
Or, 99 H + 0 = 882
Or , 99 H = 882
∴ H = 
I.e H = 8.9
Put the value of H in eq 1
So, O = 18 - H
I.e O = 18 - 8.9
∴ O = 9.1
So, number of once = 9.1
number of hundreds = 8.9
Hence The number of once is 9.1 and The number of hundreds is 8.9
Answer
-7 is correct because a negative plus a negative is always a negative
Answer:
FG || BC.
Step-by-step explanation:
In the diagram, which is not drawn to scale, DE | FG || BC.
