The ratio of boys to girls in ms. zombo's class is 33 to 22. in mr. stolarski's class it is 55 to 33. if there are 15 students
1 answer:
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For this case, the first thing we must do is define variables.
We have then:
m: original quantity of merchandise sold (in $)
We then have the following idea:
(original amount) (percent) = new amount
The new amount is the amount that Jacqueline earns for 12% of the commission on sales.
We have then:
Clearing m we have:
Answer:
The equation that solves the problem is:
The amount she sold is:
Answer:
sedan = 26 miles/gallon
truck = 17 miles/gallon
Step-by-step explanation:
try to write the text in mathematical format as a system of equations
t=truck s=sedan
first equation can be written as
t= (181-5s)/3
we can use it in the second equation and rewrite it as
7[(181-5s)/3]+6s = 275
7(181/3 -5/3s) + 6s = 275
1267/3 - 35/3s + 6s = 275
-35/3s + 18/3s = 275-1267/3
-35/3s + 18/3s = 825/3 - 1267/3
-35s + 18s = 825 -1267
-17s = -442 s = 442/17 = 26 sedan has an average of 26 miles/gallon
we use this value of s in the first equation
3t + 5*26=181 3t=181-130 t= 51/3 = 17 truck has an average of 17 miles/gallon
We have to find the" ratio of the area of sector ABC to the area of sector DBE".
Now,
the general formula for the area of sector is
Area of sector= 1/2 r²θ
where r is the radius and θ is the central angle in radian.
180°= π rad
1° = π/180 rad
For sector ABC, area= 1/2 (2r)²(β°)
= 1/2 *4r²*(π/180 β)
= 2r²(π/180 β)
For sector DBE, area= 1/2 (r)²(3β°)
= 1/2 *r²*3(π/180 β)
= 3/2 r²(π/180 β)
Now ratio,
Area of sector ABC/Area of sector DBE =
= 4/3