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patriot [66]
2 years ago
8

On a number line, a number, b, is located the same distance from 0 as another number, a, but in the opposite direction. The numb

er b varies directly with the number a. For example b = 2a equals negative 2 and StartFraction 3 Over 4 EndFraction. when a = –2a equals negative 2 and StartFraction 3 Over 4 EndFraction.. Which equation represents this direct variation between a and b?
b = –a
–b = –a
b – a = 0
b(–a) = 0
Mathematics
2 answers:
-BARSIC- [3]2 years ago
8 0

Answer:

b=-a

Step-by-step explanation:

because it just is, do not question my authority.

Your welcome....

Guest
1 year ago
um ok mom lol
den301095 [7]2 years ago
4 0

Answer: b=-a

Step-by-step explanation:

got it right on edgenuity!

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Tania has 56 liters of milk. She uses the milk to make muffins and cakes. Each batch of muffin requires 7 liters of milk and eac
mihalych1998 [28]
Write the inequalities that are given by the :

<span>x: the number of batches of muffins

y: the number of batches of cakes

</span>Each batch of muffin requires 7 liters of milk and each batch of cakes require 4 liters of milk.

=> liters of milk use = 7x  + 4y

<span>Tania has 56 liters of milk.=> 7x + 4y ≤ 56

Which means that the amount of muffins and cakes made are limited by the availability of 56 liter of milk.

The inequality 7x + 4y ≤ 56 is graphed by drawing the line 7x + 4y = 56 and shading the region below that line.

The line 7x + 4y = 56 has these x and y intercepts:

y-intercept: x =0 => 4y = 56 => y = 56/4 => 14 => point (0,14)

x-intercept => y = 0 => 7x = 56 => x = 56/7= 8  => point (8,0)

So, the line passes through the poins (0,8) and (14,0) and the solution region is below that line.

Also, you know that x and y are restricted to be positive or zero =>

x ≥ 0

y ≥ 0.

So, the solution region is restricted to the first quadrant.

That implies that the answer is:
</span><span>
Line joining ordered pairs 0, 14 and 8, 0. Shade the portion of the graph below this line which lies within the first quadrant
</span>


4 0
2 years ago
Can you Solve this 2y+4y=6-3y?
Licemer1 [7]

Answer:

\large\boxed{y=\dfrac{2}{3}}

Step-by-step explanation:

2y+4y=6-3y\\\\6y=6-3y\qquad\text{add}\ 3y\ \text{to both sides}\\\\6y+3y=6-3y+3y\\\\9y=6\qquad\text{divide both sides by 9}\\\\\dfrac{9y}{9}=\dfrac{6}{9}\\\\y=\dfrac{6:3}{9:3}\\\\y=\dfrac{2}{3}

3 0
2 years ago
A cosmetics company that makes small cylindrical bars of soap wraps the bars in plastic prior to shipping. Find the surface area
Lelu [443]
We would have two circles of 5cm diameter each, and a rectangle of the length pi*diameter and 2cm, so lets add them:
total = 2circles + rectangle
total = 2(2*pi*(5/2)^2) + pi*diameter*heigth
= 4*pi*(2.5)^2 + pi*5*2
= 109.9
that is the surface area of a bar soap 109.9 cm^2
3 0
2 years ago
Read 2 more answers
It takes Daphne 25 minutes to assemble a model plane. During her work day Daphne takes 30 minutes for lunch and one 15 minute br
natka813 [3]

Answer:

<h2>y=25p-45</h2>

Step-by-step explanation:

We first of all start by cumulating all the time she spent for break

lunch= 30min

break= 15min

total break= 45min

also the time taken to assemble one model plane 25min

let the number of hours be p

and the total number of model plane be y

The model is

y=25p-45

7 0
2 years ago
Consider a single spin of the spinner.
alex41 [277]

Answer:

"landing on a shaded portion and landing on a 3"

"landing on an unshaded portion and landing on a number less than 2 "

Step-by-step explanation:

Mutually exclusive means the events will have no intersection.

Let's look at your first choice:

"landing on a shaded portion and landing on an even number"

Landing on a shaded portion would be 1 or 4.

Landing on an even number would be 2 or 4.

There is an intersection (they contain a common element), the 4.

These events are not mutually exclusive.

Let's look at your second choice:

"landing on a shaded portion and landing on a number greater than 3"

Landing on a shaded portion would be 1 or 4.

Landing on a number greater than 3 would be just 4.

There is an intersection; they both contain 4.

These events are not mutually exclusive.

Let's look at your third choice:

"landing on a shaded portion and landing on a 3"

Landing on a shaded portion would be 1 or 4.

Landing on 3 would just be 3.

There is no common elements in the lists listed.  These events have no intersection.

These events are mutually exclusive.

Let's look at your fourth choice:

"landing on an unshaded portion and landing on an odd number"

Landing on a unshaded portion would be 2 or 3.

Landing on an odd number would be 1 or 3.

There is an intersection; they both have 3 in common.

These events are not mutually exclusive.

Let's look at your fifth choice:

"landing on an unshaded portion and landing on a number less than 2 "

Landing on an unshaded portion would 2 or 3.

Landing on a number less than 2 would be 1.

There is no intersection.

These events are mutually exclusive.

6 0
2 years ago
Read 2 more answers
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