Let
x = pounds of peanuts
y = pounds of cashews
z = pounds of Brazil nuts.
The total pounds is 50, therefore
x + y + z = 50 (1)
The total cost is $6.60 per pound for 50 pounds of mixture.
The total is equal to the sum of the costs of the different nuts.
Because the cost for peanuts, cashews, and Brazil nuts are $3, $10, and $9 respectively, therefore
3x + 10y + 9z = 50*6.8
3x + 10y + 9z = 340 (2)
There are 10 fewer pounds of cashews than peanuts, therefore
x = y + 10 (3)
Substitute (3) into (1) and (2).
y + 10 + y + z = 50
2y + z = 40 (4)
3(y + 10) + 10y + 9z = 340
13y + 9z = 310 (5)
From (4),
z = 40 - 2y (6)
Substitute (6) into (5).
13y + 9(40 - 2y) = 310
-5y = -50
y = 10
z = 40 - 2y = 40 - 20 = 20
x = y + 10 = 20
Answer:
Peanuts: 20 pounds
Cashews: 10 pounds
Brazil nuts: 20 pounds
Answer:
a = 9
b = 19
Step-by-step explanation:
DO B FIRST
The mean is the average of all the terms (numbers) in the sequence
To find the average you find the sum of the terms and divided the sum by the number of terms there are.
The mean times the number of terms equals the sum of all the terms subtract the terms that you know from the sum to get A
a = 17(10)-7-12-15-17-19-20-22-24-25
a = 170-161
a = 9
The median is found by taking the average of the two middle terms
Our middle terms are 17 and B
the median times 2 equals the sum of the two terms and then subtract the term you know from the sum
b = 18(2)-17
b = 36-17
b = 19
Answer:
6
Step-by-step explanation:
The question is incorrect.
The correct question is:
Three TAs are grading a final exam.
There are a total of 60 exams to grade.
(c) Suppose again that we are counting the ways to distribute exams to TAs and it matters which students' exams go to which TAs. The TAs grade at different rates, so the first TA will grade 25 exams, the second TA will grade 20 exams and the third TA will grade 15 exams. How many ways are there to distribute the exams?
Answer: 60!/(25!20!15!)
Step-by-step explanation:
The number of ways of arranging n unlike objects in a line is n! that is ‘n factorial’
n! = n × (n – 1) × (n – 2) ×…× 3 × 2 × 1
The number of ways of arranging n objects where p of one type are alike, q of a second type are alike, r of a third type are alike is given as:
n!/p! q! r!
Therefore,
The answer is 60!/25!20!15!
<u>Answer:</u>
Tabitha will use 12 teaspoons.
<u>Explanation: </u>
According to the question, Tabitha has a largest volume-measuring tool teaspoon, and she wants to use one-fourth cup of broth.
Given that 1 cup consists of 16 tablespoons and 1 tablespoon has 3 teaspoons.
From the data, we can calculate that;
16 tablespoons will be equal to (3*16) = 48 teaspoons.
Therefore, 1 cup = 48 teaspoons.
Substituting the data and we can calculate that 1/4 cup = 48/4 = 12 teaspoons.
