Answer: 2/3
Explanation: Assume that the number of smarties he picked is c.
Now, we are given that:
1- He picked 3 times as many cola bottles as smarties. This means that:
Number of cola bottles he picked = 3s
2- He picked twice as many smarties as marshmallows. This means that:
number of marshmallows he picked = 0.5s
Now to get the proportion o f cola bottles, we will divide the number of cola bottles by the total number of sweets as follows:
proportion of cola bottles =
Hope this helps :)
This item can be answered through the concept of fundamental principles of counting. In the first of the four digits, there are 10 possible digits. The same with all the other 3 places or digits of the code. That is,
n = 10 x 10 x 10 x 10
Giving us the answer of 10,000. Thus, there are 10,000 possible keys for the keyless entry.
Answer:
He'll need 288 cups to make a waffle on his 24 foot diameter circular griddle.
Step-by-step explanation:
In order to find out how much batter Danny needs we first need to compute the area of the first pans, since it is a circular pan their area is given by A = 2*pi*r. So we have:
Area of the first pan = 2*pi*(6/2) = 18.84 square inches
Area of the second pan = 2*pi*(24/2) = 75.36 square foots
We now need to convert these values to be in the same unit, we'll convert from square foots to square inches:
Area of the second pan = 75.36 * (12)^2 = 10851.84 square inches
We can now use a proportion knowing that the batter and the thickness of the waffles are the same. If 0.5 cup of flour can make a waffle on 18.84 square inches then x cup of flour can make a waffle on 10851.85 square inches. Writing this in a mathematical form, we have:
0.5/x = 18.84/10851.84
18.84x = 0.5*10851.85
x = 10851.85*0.5/18.84 =288 cups
Answer:
a. z = 2.00
Step-by-step explanation:
Hello!
The study variable is "Points per game of a high school team"
The hypothesis is that the average score per game is greater than before, so the parameter to test is the population mean (μ)
The hypothesis is:
H₀: μ ≤ 99
H₁: μ > 99
α: 0.01
There is no information about the variable distribution, I'll apply the Central Limit Theorem and approximate the sample mean (X[bar]) to normal since whether you use a Z or t-test, you need your variable to be at least approximately normal. Considering the sample size (n=36) I'd rather use a Z-test than a t-test.
The statistic value under the null hypothesis is:
Z= X[bar] - μ = 101 - 99 = 2
σ/√n 6/√36
I don't have σ, but since this is an approximation I can use the value of S instead.
I hope it helps!
(a) there are 8C2 = 28 ways of picking 2 girls from 8
And there are 21C4 = 5985 ways of picking 4 boys
Required number of ways for 2g / 4b = 28 * 5985 = 167,580
(b) at least 2 girls means combinations of 2g/4b , 3g,3b , 4g/2b , 5g 1b or
6 girls.
2g/4b = 167,580 ways
3g/3b = 8C3 * 21C3 = 56 * 1330 = 74,480
4g/2b = 8C4* 21C2 = 70 * 210 = 14,700
5g 1b = 8C5* 21 = 56*21 = 1176
6 girls = 8C6 = 28
adding these up we get the answer to (b) which is 257,964
